You diluted a 12.96 ml vinegar sample into a 100 ml volumetric flask with distilled water. You titrated a 25.00 mL aliquot of that solution and determined the concentration of acetic acid to 0.048 M. What was the concentration of acetic in the original sample.
You diluted a 12.96 ml vinegar sample into a 100 ml volumetric flask with distilled water....
a 25.0 ml aliquot of vinegar was diluted to 250 ml in volumetric flask. Titration of 50.0 ml aliquots of diluted solution required an average of 34.88 ml of 0.09600 M NaOH. Express the acidity of the vinegar in terms of percentage (w/v) of acetic acid.
50.00-ml. sample containing acetic acid (CH.COOH, F.W. 60.05) was transferred into a 550.0-ml. volumetric flask and diluted to the mark with water. A 25.00-ml portion of the dilute solution was titrated with 25.47 mL of 0.1012 M NaOH solution to the end point. Calculate the "% (w/v) of acetic acid in the sample. Keep appropriate number of significant figures for the result. (10 points)
5.00 mL of a solution containing a monoprotic acid was placed in a 100-mL volumetric flask, diluted to the mark with deionized water and mixed well. Then, 25.00 mL of this diluted acid solution was titrated with 0.08765 M NaOH. 9.23 mL of NaOH was required to reach the endpoint. a. What does the term monoprotic mean? b. Determine the molar ratio between the acid and NaOH. c. Calculate the moles of NaOH used in this titration. d. Calculate the...
A penny having a mass of 2.5340 g was dissolved in 20 mL of 8 M HNO3. The resulting solution was transferred to a 100.00-ml volumetric flask and diluted to the mark with water. Then, a sample solution was prepared by transferring 10.00 mL of this solution to a 25.00- ml volumetric flask, adding 2.00 mL of 15 M NH3 and diluting to the mark with waterThe concentration of [Cu(NH3)4]2+ in the sample solution (determined using a Spectro Vis spectrophotometer)...
A 10.00-g sample that contains an analyte is transferred to a 250-mL volumetric flask and diluted to volume. When a 10.00 mL aliquot of the resulting solution is diluted to 25 ml it gives a signal of 0.235 (arbitrary units). A second 10.00 mL portion of the solution is spiked with 10.00 mL of a 1.00-ppm standard solution of the analyze and diluted to 25.00 mL. The signal for the spiked sample is 0.502. Calculate the weight percent of analyte...
I need it right now, please help me?? PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
Question 1 2 pts 3.34 mL of an unknown glucose solution was diluted in a 100.00 mL of volumetric flask with distilled water. 10mL of that solution and 4.00 mL of the ferricyanide reagent was placed in a second 100.00 mL volumetric flask and diluted to the mark with distilled water. Spectrophotometric analysis of the glucose/ferricyanide solution showed that the concentration of glucose was 0.070 M. What is the concentration of glucose in the unknown solution?
Question 1 2 pts 3.34 mL of an unknown glucose solution was diluted in a 100.00 mL of volumetric flask with distilled water. 10mL of that solution and 4.00 mL of the ferricyanide reagent was placed in a second 100.00 mL volumetric flask and diluted to the mark with distilled water. Spectrophotometric analysis of the glucose/ferricyanide solution showed that the concentration of glucose was 0.070 M. What is the concentration of glucose in the unknown solution?
(4) If a 1.0L sample of 5% vinegar was diluted with distilled water so that the final volume was 2.4 L what would be the new concentration in mols dm'? (5) What concentration NaOH should be used for your lab if that is what I did with the original vinegar? (choose the best option) (A) 0.0100 M (C) 0.25 (B) 0.100 M (D) 1.00 M (E) 2.00 M (6) Potassium Hydrogen Phthalate (KHP) is used as a primary standard (to...
A 13.0 mL aliquot of a flouride sample solution was diluted to 250 mL in a volumetric flask. The F- concentration of this DILUTED sample was determined with a F- ion selective electrode and found to be 3.1 mg/L. What is the concentration of F- in the original, undiluted sample?