Calculate the capacitance in pF by using the engineer's formula C = (ε0)(d)/A . d=2.8mm A=270mm^2...
Calculate the capacitance in pF by using the engineer's formula C = (ε0)(d)/A .
d=2.8mm
A=270mm^2
(The answer is suppose to be near 0.85 pF, but I can't seem to figure out why it's not)
Homework Answers
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Calculate the capacitance in pF by using the engineer's formula
C = (ε0)(d)/A .
d=2.8mm
A=270mm^2...
Please answer question 2 part c 2. The following table is the reverse bias capacitance of...
Please answer question 2 part c
2. The following table is the reverse bias capacitance of a p+-n step junction diode. If the area of the diode is 1 x 10-2cmand the semiconductor is uniformly doped, calculate the following assuming the relative dielectric constant of the semiconductor is Ks = 10, E = 8.854 x 10-14 F/cm, 1pF=10-12F, and the plot of +2 versus V is straight line. Voltage (V) Capacitance (PF) 420 344 298 266 243 5 - (a)...
Question 10 3 pts A capacitor has a small capacitance of C. The capacitor is charged...
Question 10 3 pts A capacitor has a small capacitance of C. The capacitor is charged by placing a potential difference of V = 158 between its plates and the energy it stores is 69 J. What is the capacitance in MF? Note: 1.0 MF 10- F. Please round your answer to the nearest whole number (integer). Equation: U = CV Question 11 3 pts The figure below shows a circuit that contains four capacitors. Find (a) the equivalent capacitance,...
Capacitance 1 Part 1A Capacitance 2 Part 2B Capacitance 3 Part 2A Capacitance 4 Part 2B...
Capacitance 1
Part 1A
Capacitance
2 Part 2B
Capacitance 3
Part 2A
Capacitance
4 Part 2B
Data Sheet Trial 1 2 3 4 5 Table 1: Snap Circuits Capacitance Data Capacitance 1 Capacitance 2 Capacitance 3 Time (8) Time (6) Time (s) 5.86 0.85 1.75 5.26 1.31 1.84 3.04 1.18 1,44 4.48 D.91 1.45 S.56 1.00 1.40 5.78 .82 1.45 5.97 1.24 1,33 4.97 1.07 1.76 4.98 1.37 6.05 .85 1,45 5.40s 1.025 1.52s Capacitance 4 Time (s) 6.04 S.53...
A Review Constants Part E - Determine the equivalent capacitance across terminals a and b Learning...
A Review Constants Part E - Determine the equivalent capacitance across terminals a and b Learning Goal: To reduce series-parallel combinations of inductors or capacitors to an equivalent inductance or capacitance. Inductors in series and parallel combine like resistors in series and parallel. It is possible to use Kirchhoff's current law to find the current through the equivalent inductance. Moreover, capacitors in series combine like resistors in parallel and vice versa. It is possible to use Kirchhoff's voltage law to...
2. A student connects three capacitors G = 4.50 pF,C2 = 5.20 uF, C3 = 6.20...
2. A student connects three capacitors G = 4.50 pF,C2 = 5.20 uF, C3 = 6.20 uF to a 6.00 V battery. a. The three capacitors are connected in series across the battery. i. Find the equivalent capacitance of the circuit. ii. Calculate the total charge stored in the combination. b. The three capacitors are now connected in parallel. i. What is equivalent capacitance? ii. What is the energy stored by the combination of the capacitors? 3. A graph of...
Keep getting it wrong because I need the answer in picofarads (pF) 1. 0/2 points Previous...
Keep getting it wrong because I need the answer in picofarads
(pF)
1. 0/2 points Previous Answers PSE6 26.AE.01. Example 26.1 Parallel-Plate Capacitor Problem A parallel-plate capacitor has an area A = 1.90 X 10^4 m- and a plate separation d = 1.26 mm. Find its capacitance. Strategy Use Equation 26.3. €0. Solution From Equation 26.3, we find the following. (1.90 x 10-4 m² = (8.85 x 10-12 C2/N. 1.26 x 10-3 m X PF Your response differs significantly from...
E1. a) Draw and explain why does capacitance exist in transmission lines. (2 Marks ) b)...
E1. a) Draw and explain why does capacitance exist in transmission lines. (2 Marks ) b) 132 kV three-phasetransmissionline arranged as shown in the figure has a length of 80 km and its conductor's diameter is 1.15 cm. Calculate: i) Inductance per phase (2 Marks) ii) Capacitance per phase (2 Marks ) iii) Charging current per phase (1 Mark) 5m 5m A BI Answer in the Word document (ANSWER SHEET) and Upload as attachment below
u Review | Constants Periodic Table First, consider a capacitor of capacitance C that has a...
u Review | Constants Periodic Table First, consider a capacitor of capacitance C that has a charge Q and potential difference V. Learning Goal: To be able to calculate the energy of a charged capacitor and to understand the concept of energy associated with an electric field. The energy of a charged capacitor is given by U = QV/2, where Q is the charge of the capacitor and V is the potential difference across the capacitor. The energy of a...
Part C Find the equivalent capacitance with respect to the terminals a b for the circuit...
Part C Find the equivalent capacitance with respect to the terminals a b for the circuit shown in (Figure 2). Suppose that Ca = 31 JF Express your answer to three significant figures and include the appropriate units. OBI ? H Com= 4.615 nF Submit Previous Answers Request Answer X Incorrect; Try Again: 3 attempts remaining Figure < 1 of 2 > Part D Determine the the initial voltage drop for the equivalent capacitance with respect to the terminals a...
How to reach from this formula 2 D 2 D where 2C C D 2C (C,+C)...
How to reach from this formula 2 D 2 D where 2C C D 2C (C,+C) O S and t C C D to this formula ? ( i need the solution with steps) min TC - ChC)
Please answer question 2 part c
2. The following table is the reverse bias capacitance of a p+-n step junction diode. If the area of the diode is 1 x 10-2cmand the semiconductor is uniformly doped, calculate the following assuming the relative dielectric constant of the semiconductor is Ks = 10, E = 8.854 x 10-14 F/cm, 1pF=10-12F, and the plot of +2 versus V is straight line. Voltage (V) Capacitance (PF) 420 344 298 266 243 5 - (a)...
Question 10 3 pts A capacitor has a small capacitance of C. The capacitor is charged by placing a potential difference of V = 158 between its plates and the energy it stores is 69 J. What is the capacitance in MF? Note: 1.0 MF 10- F. Please round your answer to the nearest whole number (integer). Equation: U = CV Question 11 3 pts The figure below shows a circuit that contains four capacitors. Find (a) the equivalent capacitance,...
Capacitance 1
Part 1A
Capacitance
2 Part 2B
Capacitance 3
Part 2A
Capacitance
4 Part 2B
Data Sheet Trial 1 2 3 4 5 Table 1: Snap Circuits Capacitance Data Capacitance 1 Capacitance 2 Capacitance 3 Time (8) Time (6) Time (s) 5.86 0.85 1.75 5.26 1.31 1.84 3.04 1.18 1,44 4.48 D.91 1.45 S.56 1.00 1.40 5.78 .82 1.45 5.97 1.24 1,33 4.97 1.07 1.76 4.98 1.37 6.05 .85 1,45 5.40s 1.025 1.52s Capacitance 4 Time (s) 6.04 S.53...
A Review Constants Part E - Determine the equivalent capacitance across terminals a and b Learning Goal: To reduce series-parallel combinations of inductors or capacitors to an equivalent inductance or capacitance. Inductors in series and parallel combine like resistors in series and parallel. It is possible to use Kirchhoff's current law to find the current through the equivalent inductance. Moreover, capacitors in series combine like resistors in parallel and vice versa. It is possible to use Kirchhoff's voltage law to...
2. A student connects three capacitors G = 4.50 pF,C2 = 5.20 uF, C3 = 6.20 uF to a 6.00 V battery. a. The three capacitors are connected in series across the battery. i. Find the equivalent capacitance of the circuit. ii. Calculate the total charge stored in the combination. b. The three capacitors are now connected in parallel. i. What is equivalent capacitance? ii. What is the energy stored by the combination of the capacitors? 3. A graph of...
Keep getting it wrong because I need the answer in picofarads
(pF)
1. 0/2 points Previous Answers PSE6 26.AE.01. Example 26.1 Parallel-Plate Capacitor Problem A parallel-plate capacitor has an area A = 1.90 X 10^4 m- and a plate separation d = 1.26 mm. Find its capacitance. Strategy Use Equation 26.3. €0. Solution From Equation 26.3, we find the following. (1.90 x 10-4 m² = (8.85 x 10-12 C2/N. 1.26 x 10-3 m X PF Your response differs significantly from...
E1. a) Draw and explain why does capacitance exist in transmission lines. (2 Marks ) b) 132 kV three-phasetransmissionline arranged as shown in the figure has a length of 80 km and its conductor's diameter is 1.15 cm. Calculate: i) Inductance per phase (2 Marks) ii) Capacitance per phase (2 Marks ) iii) Charging current per phase (1 Mark) 5m 5m A BI Answer in the Word document (ANSWER SHEET) and Upload as attachment below
u Review | Constants Periodic Table First, consider a capacitor of capacitance C that has a charge Q and potential difference V. Learning Goal: To be able to calculate the energy of a charged capacitor and to understand the concept of energy associated with an electric field. The energy of a charged capacitor is given by U = QV/2, where Q is the charge of the capacitor and V is the potential difference across the capacitor. The energy of a...
Part C Find the equivalent capacitance with respect to the terminals a b for the circuit shown in (Figure 2). Suppose that Ca = 31 JF Express your answer to three significant figures and include the appropriate units. OBI ? H Com= 4.615 nF Submit Previous Answers Request Answer X Incorrect; Try Again: 3 attempts remaining Figure < 1 of 2 > Part D Determine the the initial voltage drop for the equivalent capacitance with respect to the terminals a...
How to reach from this formula 2 D 2 D where 2C C D 2C (C,+C) O S and t C C D to this formula ? ( i need the solution with steps) min TC - ChC)
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