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In a plot of 1/V against 1/[S] for an enzyme-catalyzed reaction, the presense of a non-competitive...

In a plot of 1/V against 1/[S] for an enzyme-catalyzed reaction, the presense of a non-competitive inhibitor will:

a) leave the intercept on the 1/V axis unchanged

b)give parallel straight lines

c) move the intercept on the 1/[S] axis closer to zero

d) leave the intercept of the 1/[S] axis unchanged

e) move the intercept on the 1/[S] axis closer to zero and leave the intercept on the 1V axis unchanged

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Answer #1

In case of non competitive inhibitor, the following graoh is obtained:

In this graph, the non competitive inhinitor and without inhibitor lines found at the same point on 1/[S] axis. That's why there is found same Km value.

The intercept on 1/V are found at different points.

That's why right answer is :

d) leave the intercept of the 1/[S] axis unchanged

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