A water molecule is asymmetrical, with one end positively charged and the other negatively charged. It...
A water molecule is asymmetrical, with one end positively charged and the other negatively charged. It has a dipole moment whose magnitude is measured to be 6.2 × 10−30 C·m. If the dipole moment is oriented perpendicular to an electric field whose magnitude is 9 × 105 N/C, what is the magnitude of the torque on the water molecule?
Homework Answers
torque on dipole is given by
T = PE
T = 6.2* 10^-30* 9* 10^5
T = 5.58.10^-24 Nm
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