Assume that all grade-point averages are to be standardized on a scale between 0 and 4. How many grade-point averages must be obtained so that the sample mean is within 0.008 of the population mean? Assume that a 95% confidence level is desired. If using the range rule of thumb, sigma can be estimated as StartFraction range Over 4 EndFraction equalsStartFraction 4 minus 0 Over 4 EndFraction equals1. Does the sample size seem practical?
Answer
By range rule of thumb
sigma = range/4
= 4/4
= 1
Given that
margin of error(E)= 0.008
sigma = 1
z critical = 1.96
sammple size n= ((z*sigma)/E)^2
=((1.96*1)/0.008)^2
= 245^2
= 60025
No, sample size dont seem practical because sampling a total of 60025 people is too time consuming process
Assume that all grade-point averages are to be standardized on a scale between 0 and 4....
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