The rate at which popcorn pops was measured at two different temperatures. How many times faster does the popcorn pop at 250.0 °C compared with that at 150.0 °C when the activation energy is 53.8 kJ/mol?
Activation energy = 53.8 kJ/mol
temperature T1 = 150 oC = 423 K
T2 = 250 oC = 523 K
ln (k2 / k1) = Ea / R [1 / T1 - 1/ T2]
ln (k2 / k1) = 53.8 / 8.314 x 10^-3 [1 / 423 - 1/523]
(k2 / k1) = 18.63
rate faster 18.6 times
The rate at which popcorn pops was measured at two different temperatures. How many times faster...
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