Question

Write the output of the two codes below, unless there is a compiler error or a runtime error. In those cases, write ​CE​ or ​RE​, respectively, and explain why those errors occur. If the code produces an infinite loop, write “​LE:​ ​infinite loop​”.

public class ForLoopsDemo{
public static void main(String[] args){ int x = 4;
fint x = 4;
for( int i = 0; i < x; i++ ){
} }
for( int j = 0; j < 2*i+1; j++)}
System.out.print("#");
}
System.out.println();
}

  

Answer 1

public class ForLoopsDemo{
public static void main(String[] args)

{

int x = 4;
fint x = 4; // "fint" is not any Data Type of java and variable x is already defined in method

for( int i = 0; i < x; i++ ){
} } //misplaced closing brace before the for statement (syntax error)
for( int j = 0; j < 2*i+1; j++)} //opening brace is missed (syntax error)
System.out.print("#");
}
System.out.println();
} // missing curly braces, to end a class without including the closing curly brace will generate the error and this is syntax error

The above program contain the Compiler Error(CE)

Compile-time errors are generally syntax or semantics errors. These error get detected by compiler and can get fixed at the time of code development.

When you run this program 18 error will occur

ERROR Result

Corrected Program:-

public class ForLoopsDemo{
public static void main(String[] args)
{
int x = 4;
for( int i = 0; i < x; i++ )
{
for( int j = 0; j < 2*i+1; j++)
{
System.out.print("#");
}
System.out.println();
}
}
}

output

#
###
#####
#######