For each problem in this assignment, first use hypothesis testing to answer the question. Then create a confidence interval/bound as needed regarding the problem and provide an estimate of the p-value associated with the result. The estimate of the p-value may be a bound and not an exact value.
month |
Philly |
Indy |
Philly - Indy |
Jan |
40 |
38 |
2 |
Feb |
38 |
40 |
-2 |
Mar |
49 |
50 |
-1 |
Apr |
60 |
62 |
-2 |
May |
71 |
71 |
0 |
Jun |
80 |
81 |
-1 |
Jul |
87 |
84 |
3 |
Aug |
86 |
84 |
2 |
Sep |
81 |
82 |
-1 |
Oct |
70 |
70 |
0 |
Nov |
60 |
59 |
1 |
Dec |
48 |
43 |
5 |
average |
64.2 |
63.7 |
0.5 |
standard deviation |
17.6 |
17.6 |
2.15 |
![]() |
Philly | Indy |
Jan | 40 | 38 |
Feb | 38 | 40 |
Mar | 49 | 50 |
Apr | 60 | 62 |
May | 71 | 71 |
Jun | 80 | 81 |
Jul | 87 | 84 |
Aug | 86 | 84 |
Sep | 81 | 82 |
Oct | 70 | 70 |
Nov | 60 | 59 |
Dec | 48 | 43 |
t-Test: Two-Sample Assuming Equal Variances | ||
Philly | Indy | |
Mean | 64.16666667 | 63.6666667 |
Variance | 309.7878788 | 310.424242 |
Observations | 12 | 12 |
Pooled Variance | 310.1060606 | |
Hypothesized Mean Difference | 0 | |
df | 22 | |
t Stat | 0.069548938 | |
P(T<=t) one-tail | 0.472590494 | |
t Critical one-tail | 1.321236742 | |
P(T<=t) two-tail | 0.945180987 | |
t Critical two-tail | 1.717144374 |
After Entering the values in Excel we can easily analyse the difference of means between phily and Indy variable
steps to do in Excel
1) Enter Values in Excel as shown above in Image
2 ) Go to Data tab and click Data analysis - t-Test: Two-Sample Assuming Equal Variances - Select two variables range and put alfa = 0.10
and click OK to get the results.
Here
we can see from the above results that p values is 0.95 >
= 0.10 which
Implies Ho is We do not reject Ho
Which implies that Average temperature of Philly and Indy are
not different at = 0.10 level of
Significance
For each problem in this assignment, first use hypothesis testing to answer the question. Then create...
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