A 500 kg cart is rolling to the right at 3.50 m/s. A 70.0 kg man is standing on the right end of the cart.
What is the speed of the cart if the man suddenly starts running to the left with a speed of 10.0 m/s relative to the cart?
Express your answer with the appropriate units.
using conservation of momentum
(m1 + m2) v = m1 v1 + m2 v2
now velocity of cart with respect to ground
v1 = v2 - 10
then
(500 + 70)* 3.5 = 70* (v2 - 10 )+ 500 v2
v2 = 4.728 m/s
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