It was experimentally determined from three trials that an object had a density of 0.96, 0.99,...
It was experimentally determined from three trials that an object had a density of 0.96, 0.99, and 0.95 g/mL. What is the average density and standard deviation of this object?
a. 0.967 (±0.021) g/mL
b. 0.967 (±0.02) g/mL
c. 0.97 (±0.02) g/mL
d. 0.96 (±0.02) g/mL
Homework Answers
Average density (av) = sum of all measurements / number of measurements = (0.96 + 0.99 + 0.95) / 3 = 0.96
Standard deviation (SD) = [
(av -
measurement)2 / number of
measurements]1/2
= [{(0.96 - 0.96)2 + (0.96 - 0.99)2 + (0.96 - 0.95)2 } / 3]1/2 = 0.02 g/ml
Answer is d. 0.96 (+- 0.02) g/ml
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c. the random
uncertainty associated...
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