In a converging (convex) lens, positive magnification m means the image is virtual, erect and lies...
In a converging (convex) lens,
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positive magnification m means the image is virtual, erect and lies in the same side of the object. |
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positive magnification m means the image is real, inverted, and on the same side of the object. |
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negative magnification m means the image is virtual, erect, and on the opposite side of the object. |
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Homework Answers
In converging lens positive magnification means the image is virtual,erect and lies on the same side of object.
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In a converging (convex) lens,
positive magnification m means the image is
virtual, erect and lies...
A converging lens with a focal length of 12.0cm forms a virtual image 8.00mm tall. Image...
A converging lens with a focal length of 12.0cm forms a virtual image 8.00mm tall. Image is 17.0cm from the lens. Calculate (a)the position of the object, (b)magnification of the lens, (c)height of the object. (d)Is the image upright or inverted? (e) Are the object and image on the same side or opposite sides of the lens? (f) Draw ray-diagram
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
An object is placed 50.0cm in front of a lens. The image forms on the same...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
A convex lens produces a magnification of -2. This means the image is: A) Twice the...
A convex lens produces a magnification of -2. This means the image is: A) Twice the size of object and inverted B) Half the size of object and inverted C) Twice the size of object and upright D) Half the size of object and upright
1. What can one say about the image produced by a thin lens that produces a positive magnification? a. It is real...
1. What can one say about the image produced by a thin lens that produces a positive magnification? a. It is real and inverted b. It is real and erect. c.It is virtual and inverted. d. It is virtual and erect. 2.If the diameter of a lens is reduced, what happens to the magnification produced by the lens? a. It increases b. It decreases c. It is unchanged
A diverging lens with a focal length of -47.0 cm forms a virtual image 7.50 mm...
A diverging lens with a focal length of -47.0 cm forms a virtual image 7.50 mm tall, 17.5 cm to the right of the lens.Part A Determine the position of the object. Part B Determine the size of the object.Part C Is the image erect or inverted? erect invertedPart D Are the object and image on the same side or opposite sides of the lens? The object and image are on the same side. The object and image are on...
7. Consider a converging lens that has a focal length (f). Which one of these is...
7. Consider a converging lens that has a focal length (f). Which one of these is correct about the image when the object is placed in front of the lens at a distance of (f/4 )? The image is real, erect, and diminished The image is real, erect, and magnified The image is virtual, inverted, and magnified The image is virtual, erect, and magnified The image is virtual, erect, and has the same size as the object The image is...
The lens shown above is a O bi-convex diverging lens. bi-convex converging lens. bi-concave diverging lens....
The lens shown above is a O bi-convex diverging lens. bi-convex converging lens. bi-concave diverging lens. Obi-concave converging lens. Under the sign convention rules for lenses, a negative focal length means that the lens is planar. converging. bifocal. diverging. An object is placed 30 cm from a converging lens with a focal length of 20 cm. The image will appear right side up 12 cm from the lens on the same side of the lens. right side up 60 cm...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
A convex lens produces a magnification of -2. This means the image is: A) Twice the size of object and inverted B) Half the size of object and inverted C) Twice the size of object and upright D) Half the size of object and upright
A diverging lens with a focal length of -47.0 cm forms a virtual image 7.50 mm tall, 17.5 cm to the right of the lens.Part A Determine the position of the object. Part B Determine the size of the object.Part C Is the image erect or inverted? erect invertedPart D Are the object and image on the same side or opposite sides of the lens? The object and image are on the same side. The object and image are on...
The lens shown above is a O bi-convex diverging lens. bi-convex converging lens. bi-concave diverging lens. Obi-concave converging lens. Under the sign convention rules for lenses, a negative focal length means that the lens is planar. converging. bifocal. diverging. An object is placed 30 cm from a converging lens with a focal length of 20 cm. The image will appear right side up 12 cm from the lens on the same side of the lens. right side up 60 cm...
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