What is O3, O2, and O Step1: Cl + O3 ⇄ ClO + O2 Step2: ClO...
What is O3, O2, and O
Step1: Cl + O3 ⇄ ClO + O2
Step2: ClO + O ⇄ Cl + O2
Total: O3 + O ⇄ 2O2
a. Cl(catalyst) b. O3 c. ClO(intermediate) d. O2 e. O
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1.) What is the transition state in the following reaction? Cl + O3 ⟶ ClO +...
1.) What is the transition state in the following reaction? Cl + O3 ⟶ ClO + O2 ClO + O ⟶Cl + O2 O3 + O ⟶2O2 (overall reaction) A) Cl B) O3 C) O D) ClO E) O2 2.) What is the catalyst in the following reaction? Cl + O3 ⟶ClO + O2 ClO + O ⟶Cl + O2 O3 + O ⟶2O2 (overall reaction) A) Cl B) O3 C) O D) ClO E) O2
Identify the catalyst and intermediate in the following multi-step mechanism: step 1: Br+O3 -> BrO+ O2...
Identify the catalyst and intermediate in the following multi-step mechanism: step 1: Br+O3 -> BrO+ O2 step 2: BrO + O3 -> Br +2O2 a. There is no catalyst or intermediate in the above reaction b. Catalyst: O2 Intermediate: O3 c. Catalyst: BrO∙ Intermediate: Br∙ d. Catalyst: O3 Intermediate: O2 e. Catalyst: Br∙ Intermediate BrO
determine delta H for Cl(g) + O3(g) —> ClO(g) +O2(g) 2 O3(g) -> 3 O2(g). H=-29.90...
determine delta H for Cl(g) + O3(g) —> ClO(g) +O2(g) 2 O3(g) -> 3 O2(g). H=-29.90 kj/mol ClO(g) + O3(g) -> Cl(g) + 2 O2(g). H=+24.18 kj/mol report to 4 sigfigs
Use Hess?s law to calculate ?G°rxn using the following information. ClO(g) + O3(g) ? Cl(g) +...
Use Hess?s law to calculate ?G°rxn using the following information. ClO(g) + O3(g) ? Cl(g) + 2 O2(g) ?G°rxn = ? 2 O3(g)? 3 O2(g) ?G°rxn = +489.6 kJ Cl(g) + O3(g) ? ClO(g) + O2(g) ?G°rxn = -34.5 kJ
1) 2) 3) C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ...
1)
2)
3)
C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A proposed...
2. Determine the ∆H º for the third reaction; is it exothermic ? ClO(g) + O3(g)...
2. Determine the ∆H º for the third reaction; is it exothermic ? ClO(g) + O3(g) --> Cl(g) + 2 O2(g) ∆Hº = -29.90 kJ/mol 2 O3(g) --> 3 O2(g) ∆Hº = +24.18 kJ/mol Cl(g) + O3(g) --> ClO(g) + O2(g) ∆Hº = ????
Reaction A $$O3(g)+Cl(g)ClO(g)+O2(g) $$A=2.93×10−11 cm3molecule • s and Ea=2.16 kJmol...
Reaction A
$$O3(g)+Cl(g)ClO(g)+O2(g)
$$A=2.93×10−11 cm3molecule • s and
Ea=2.16 kJmol
Reaction B
$$O3(g)+NO(g)NO2(g)+O2(g)
$$A=2.34×10−12 cm3molecule •
s Ea=11.6 kJmol
On the basis of the frequency factors and activation energy
values above, calculate the rate constant for Reaction A at 298
K.
On the basis of the frequency factors and activation energy
values above, calculate the rate constant for Reaction B at 298
K.
We were unable to transcribe this imageWe were unable to transcribe this image
One of the components of smog is ozone,O3, a colorless, toxic gas. It is a very...
One of the components of smog is ozone,O3, a colorless, toxic gas. It is a very strong oxidizing agent and causes respiratory illnesses. Ozone is produced in the lower atmosphere due to the catalytic effect of nitric oxide, NO, a byproduct of the combustion process in car engines. However, in the upper atmosphere ozone is a very useful gas, because it absorbs ultraviolet radiation and protects the earth from this high energy, damaging radiation. It is referred to as the...
1) 2) 3) 4) C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220...
1)
2)
3)
4)
C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A...
Determine the equilibrium constant for the following reaction at 298 K. Cl(g) + O3(g) → ClO(g)...
Determine the equilibrium constant for the following reaction at 298 K. Cl(g) + O3(g) → ClO(g) + O2(g) ΔG° = - 34.5 kJ Please explain how you enter it into the calculator I get 1.23*10^-14. Which is incorrect the answer is 1.12*10^-6.
1)
2)
3)
C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A proposed...
Reaction A
$$O3(g)+Cl(g)ClO(g)+O2(g)
$$A=2.93×10−11 cm3molecule • s and
Ea=2.16 kJmol
Reaction B
$$O3(g)+NO(g)NO2(g)+O2(g)
$$A=2.34×10−12 cm3molecule •
s Ea=11.6 kJmol
On the basis of the frequency factors and activation energy
values above, calculate the rate constant for Reaction A at 298
K.
On the basis of the frequency factors and activation energy
values above, calculate the rate constant for Reaction B at 298
K.
We were unable to transcribe this imageWe were unable to transcribe this image
1)
2)
3)
4)
C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A...
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