When combining two 2:1 selector, enable signal is usually active-low, what if it is active high? Which is better?
If the signal's meaning is considered active or asserted when the input voltage is above the minimum high threshold voltage of the receiver, then it is called active high.
If the signal's meaning is considered active or asserted when the input voltage is below the maximum low threshold voltage of the receiver, then it is called active low.
An active high clock enable means the clock is enabled when the input is high.
An active low reset means the circuit is reset when the input is driven low.
Open-drain signals are typically active low. This makes it easier to interface to various voltage standards by pulling up (inactive state for active low) to the proper interface voltage (one which meets minimum high without exceeding absolute maximums).
When combining two 2:1 selector, enable signal is usually active-low, what if it is active high?...
Can you give me the truth table for a 4:1 ACTIVE LOW selector with an ACTIVE LOW enable?
3. Consider a tri-state inverter with an active-high enable. (So the output of the buffer is enabled when the enable signal is high, and is in tri-state when the enable signal is low.) Complete the truth table. En A Out 0 0 0 1 10 AoOut En (active high) 4. Consider an open-collector buffer. Complete the truth table. A OU 1 AO-Out
Use 3-to-8 lines decoders to achieve the following: (Decoders should have one active-low ENABLE input, active-high binary code inputs, and active-low outputs. You can use additional gates) F = Σ A,B,C,D (2,4,6,14)
using five(5),2 to 4 line decoders with active low enable inputs and active low outputs, and a 4 input NAND gate, draw the circuit diagram that implements the following function. F(W,X,Y,Z) = (Z( W'( X'Y +XY')+W(XY+XY')
Each FF has an asynchronous active-low clear signal. The asynchronous active-low clear signal clears the FF and uses this signal to set the initial output of the FF to zero. (Active-low clear: clear when clear signal is low (0)). Implement negative edge-triggered T FF using Verilog code. At this time, The interface is as follows. Module t_ff (input t, input clk, input clearb, output q); How the waveform of q changes when the value of input t changes sequentially to...
1. Provide the function table of a 3-to-8 active-low output decoder with active-low enable input. 2. A function f (D,C,B,A) is synthesized by a 4-to-16 decoder as in Figure 1. Derive the canonical SOP expression for the function f(D,C,B,A). AO (LSB) B-1 C-2 f(D,C.B.A) (LSB) ib 2 b 3 45 5 6b 7b 8b 3 ( MSB) 9 p 10 11 b 12 b 13 d EN 14 b ( MSB) 15 D Figure 1
using 4 to 1 line multiplaxors that have tri-state outputs with an active low enable input,along with a 2 to 4 line active low output decoder, draw a schematic block diagram of a 16 to 1 multiplexor
WRITE IN SYSTEM VERILOG:
Write a HDL code for 1 bit D-register with a rising edge clock, a synchronous active-low reset and an asynchronous active-high enable pin. B2.
Write a HDL code for 1 bit D-register with a rising edge clock, a synchronous active-low reset and an asynchronous active-high enable pin. B2.
Active Low-pass and High-pass Filters for Crossover Circuitry
(PSPICE)
Design a first order active high-pass filter with cut-off
frequency of 1 kHz & gain 20dB.
Design a first order active low-pass filter with cut-off
frequency of 1 kHz & gain 20dB.
Plot the magnitude and phase responses of the active high-pass
and low-pass filters you have designed using PSpice (Use UA741 Op
amp and ±12V dual supply).
Connect your active low-pass and high-pass filters as shown in
Fig. 1-b. Assume...
The type of active filter shown in below is two-pole, low-pass two-pole, high-pass four-pole, low-pass four-pole, high-pass