2. In Mendelian segregation, a “dihybrid self” represents a F1 dihybrid that was crossed with itself...

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2. In Mendelian segregation, a “dihybrid self” represents a F1 dihybrid that was crossed with itself...

2. In Mendelian segregation, a “dihybrid self” represents a F1 dihybrid that was crossed with itself (AaBb x AaBb). What are the expected F2 phenotypic ratios, if the F1 cross was actually Aa; Bb x Aa; bb? Show a punnet square.

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Answer 1

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Aa;Bb x Aa;bb ---Parents

	Ab	ab
AB	AA; Bb	Aa; Bb
Ab	AA; bb	Aa; bb
aB	Aa; Bb	aa; Bb
ab	Aa; bb	aa; bb

A_B_ phenotype = AA;Bb + Aa; Bb = 1+2 = 3

A_bb phenotype = AA; bb + Aa bb = 1+2 = 3

aaB_ phenotype = aaBb = 1

aabb = 1 = 1

The phenotypic ratio = 3:3:1:1

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