Question

A windmill has an initial angular momentum of 8550 kg⋅m2/s . The wind picks up, and...

A windmill has an initial angular momentum of 8550 kg⋅m2/s . The wind picks up, and 5.56 s later the windmill's angular momentum is 9600 kg⋅m2/s .

What was the torque acting on the windmill, assuming it was constant during this time?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer:

To find the torque acting on the windmill we use following relation:

Add a comment
Know the answer?
Add Answer to:
A windmill has an initial angular momentum of 8550 kg⋅m2/s . The wind picks up, and...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 10. The angular momentum of a flywheel having a rotational inertia of 0.140 kg m2 about...

    10. The angular momentum of a flywheel having a rotational inertia of 0.140 kg m2 about its central axis decreases from 3.00 to 0.800 kg m'/s in 1.50 s. (a) What is the magnitude of the average torque acting on the flywheel about its central axis during this period? (b) Assuming a constant angular acceleration, through what angle does the flywheel turn? (c) How much work is done on the wheel? (d) What is the average power of the flywheel?...

  • A windmill has three blades that can extend or retract depending on the wind speed. Each...

    A windmill has three blades that can extend or retract depending on the wind speed. Each blade can be approximated by a rod with a mass of 270 kg that is fixed at one end. The moment of inertia of each blade is 1/3 ML2, where L is the length of the blade. Each blade is 9.0 m long. Calculate the total moment of inertia of the windmill. The wind causes the windmill to rotate with a constant speed in...

  • Calculate the angular momentum, in kg · m2/s, of an ice skater spinning at 6.00 rev/s...

    Calculate the angular momentum, in kg · m2/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg · m2. (a) Calculate the angular momentum, in kg . m/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg . m2. kg. m/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his...

  • A rigid object rotating about a fixed axis has an angular momentum L=7.0 kg m2 /s...

    A rigid object rotating about a fixed axis has an angular momentum L=7.0 kg m2 /s and a kinetic energy K=21.3 J. What is the rotational inertia I of the object? A rigid object rotating about a fixed axis has an angular momentum L=7.0 kg m2/s and a kinetic energy K=21.3 J. What is the rotational inertial of the object? Select one: I=1.27 kg m 2 1=1.61 kg m 2 1=0.92 kg m^2 I=1.15 kg m 2 I=1.50 kg m...

  • (a)Calculate the angular momentum (in kg · m2/s) of Mars in its orbit around the Sun....

    (a)Calculate the angular momentum (in kg · m2/s) of Mars in its orbit around the Sun. (The mass of Mars is 6.420 ✕ 1023 kg, the orbital radius is 2.279 ✕ 108 km and the orbital period is 1.88 y.) kg · m2/s (b)Compare this angular momentum with the angular momentum of Mars on its axis. (The radius of Mars is 3.396 ✕ 103 km and the rotation period is 24.62 h.) Lorbital Lrotation

  • A 10.4 kg mass moving in a circle (diameter 1.9 m). The angular momentum varies in...

    A 10.4 kg mass moving in a circle (diameter 1.9 m). The angular momentum varies in time as I acting on the mass at 5.2 s? Enter your answer to the tenth's place. 4.9t. What is the net torque

  • In a long jump, an athlete leaves the ground with an initial angular momentum that tends...

    In a long jump, an athlete leaves the ground with an initial angular momentum that tends to rotate her body forward, threatening to ruin her landing. To counter this tendency, she rotates her outstretched arms to "take up" the angular momentum (see the figure below). In 0.730 s, one arm sweeps through 0.500 rev and the other arm sweeps through 1.000 rev. Treat each arm as a thin rod of mass 3.9 kg and length 0.56 m, rotating around one...

  • Tutorial: Angular Momentum and Torque III. Angular Momentum The angular momentum of a point particle is...

    Tutorial: Angular Momentum and Torque III. Angular Momentum The angular momentum of a point particle is defined by: L = ixp. Here, is a vector that points from the point of rotation (or point around which the angular momentum is calculated) to the location of the particle and p = mb is the linear momentum of the particle. A Your little brother Joey is playing with his toy airplane. The airplane is tied to a string and its motor makes...

  • Calculate the angular momentum (in kg · m2/s) of Mercury in its orbit around the Sun....

    Calculate the angular momentum (in kg · m2/s) of Mercury in its orbit around the Sun. (The mass of Mercury is 3.300 ✕ 1023 kg, the orbital radius is 5.790 ✕ 107 km and the orbital period is 0.241 y.) 9.213e32 is wrong

  • 6. Angular Momentum and Torque on a Meteor A meteor enters Earth's atmosphere and is observed...

    6. Angular Momentum and Torque on a Meteor A meteor enters Earth's atmosphere and is observed by someone on the ground before it burns up in the atmosphere. The vector 25 m i +25 m j gives the position of the meteor with respect to observer. At the instant the observer sees the meteor, it has linear momentum p 1.5 kg -2.0) m/s 3 and it is accelerating at a constant rate of 2.0 m/s(-3) along its path, which for...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT