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Derive the Michaelis -Mantens equation for enzymatic reaction ? What will happen if there are no...

Derive the Michaelis -Mantens equation for enzymatic reaction ? What will happen if there are no enzyme in this process.

Bio chemical question

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Answer #1

A simple model of enzyme action:

We would like to know how to recognize an enzyme that behaves according to this model. One way is to look at the enzyme's kinetic behavior -- at how substrate concentration affects its rate. So we want to know what rate law such an enzyme would obey. If a newly discovered enzyme obeys the rate law derived from this model, then it's reasonable to assume that the enzyme reacts according to this model. It's not proof that the model is correct, but at least it tells us that kinetics does not rule it out.

Let's derive a rate law from this model.

For this model, let V 0 be the initial velocity of the reaction. Then

V 0 = k cat [ES]. (2)

The maximum velocity V max occurs when the enzyme is saturated -- that is, when

all enzyme molecules are tied up with S, or

[ES] = [E] total .

So V max = k cat [E] total . (3)

We want to express V 0 in terms of measurable quantities, like [S] and [E] total , so we can see how to test the mechanism by experiments in kinetics. So we must replace [ES] in (2) with measurables.

During the initial phase of the reaction, as long as the reaction velocity remains constant, the reaction is in a

steady state , with ES being formed and consumed at the same rate. During this phase, the rate of formation of [ES] equals its rate of consumption. According to model (1),

Rate of formation of ES = k 1 [E][S].

Rate of consumption of ES = k -1 [ES] + k cat [ES].

So in the steady state, k -1 [ES] + k cat [ES] = k 1 [E][S]. (4)

Remember that we are trying to solve for [ES] in terms of measurables, so that we can replace it in (2). First, collect the kinetic constants in (4):

(k -1 + k cat ) [ES] = k 1 [E][S],

and (k -1 + k cat)/k 1 = [E][S]/[ES]. (5)

To simplify (5), first group the kinetic constants by defining them as K m :

K m = (k -1 + k cat)/k 1 (6)

and then express [E] in terms of [ES] and [E]total:

[E] = [E] total - [ES] (7)

Substitute (6) and (7) into (5):

Km = ([E] total - [ES]) [S]/[ES] (8)

Solve (8) for [ES]: First multiply both sides by [ES]:

[ES] K m = [E] total [S] - [ES][S]

Then collect terms containing [ES] on the left:

[ES] K m + [ES][S] = [E] total [S]

Factor [ES] from the left-hand terms:

[ES](K m + [S]) = [E] total [S]

and finally, divide both sides by (K m + [S]):

[ES] = [E] total [S]/(K m + [S]) (9)

Substitute (9) into (2): V 0 = k cat [E] total [S]/(K m + [S]) (10)

Recalling (3), substitute V max into (10) for k cat [E] total :

V0 = Vmax [S]/(K m + [S]) (11)

This equation expresses the initial rate of reaction in terms of a measurable quantity, the initial substrate concentration. The two kinetic parameters, V max and K m , will be different for every enzyme-substrate pair.

Equation (11), the Michaelis-Menten equation, describes the kinetic behavior of an enzyme that acts according to the simple model (1). Equation (11) is of the form

y = ax/(b + x) (does this look familiar?)

This is the equation of a rectangular hyperbola, just like the saturation equation for the binding of dioxygen to myoglobin.

Equation (11) means that, for an enzyme acting according to the simple model (1), a plot of V 0 versus [S] will be a rectangular hyperbola. When enzymes exhibit this kinetic behavior, unless we find other evidence to the contrary, we assume that they act according to model (1), and call them Michaelis-Menten enzymes.

2 .An enzyme is a type of protein found within a cell. Enzymes create chemical reactions in the body. They actually speed up the rate of a chemical reaction to help support life.
The enzymes in your body help to perform very important tasks. These include building muscle, destroying toxins, and breaking down food particles during digestion.
An enzyme’s shape is tied to its function. Heat, disease, or harsh chemical conditions can damage enzymes and change their shape. When this happens, an enzyme doesn’t work anymore. This affects the body processes the enzyme helped support.
Enzymes are produced naturally in the body.
For example, enzymes are required for proper digestive system function. Digestive enzymes are mostly produced in the pancreas, stomach, and small intestine. But even your salivary glands produce digestive enzymes to start breaking down food molecules while you’re still chewing. You can also take enzymes in pill form if you’re having certain digestive problems.

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