derive michaelis menten equation
please show steps
Michaelis Menten equation provides an idea on enzyme kinetics when the enzyme concentration is low, which relates to in vitro kinetics. When an enzyme acts on its substrate, the enzyme initially forms an Enzyme-substrate complex, which is then converted into product and free enzyme is released. In the initial stages of a reaction, the product concentration is very little, and the reverse reaction can be ignored. We also assume that concentration of substrate is much higher than the enzyme concentration. This is given in the equation shown below:
Where E = enzyme
S = substrate
ES = enzyme substrate complex
K1, k2, and k3 are rate constants
The rate of the process (v) to the change in product formation is written as a function of time. It is written as follows:
In a reaction, the concentration of enzyme-substrate complex (ES) cannot be measured experimentally. It is alternatively represented as the enzyme bound (ES) to the enzyme unbound (E) to the substrate. The fraction of bound enzyme is expressed as follows:
Where Et is the total enzyme concentration. Multiply both sides with Et, we get the following equation:
If both the numerator and denominator of the right-hand side of equation 4 is divided by 1/[ES], we come to the following equation:
Equation (5) says that the rate of change of [ES] with time is zero:
Another steady state assumption is that the rate of formation of [ES] equals the rate of breakdown of [ES]. This can be mathematically represented as follows:
This shows the rate of formation of enzyme substrate complex and the two ways of break down of the complex. Equation (6) can be rearranged to get the ratio of:
The Michaelis constant (km) is expressed as given below:
Substitute Km into equation 7, we get:
Substitute equation 9 in equation 5, we get the following:
Multiply the numerator and denominator of the right hand side of equation 10 by [S], we get:
Now substitute the value of [ES] in equation 2, we get
When the substrate concentration is far higher than the enzyme concentration, all the catalytic sites are saturated and k3[Et] equals Vmax; the maximum velocity of the reaction that can be obtained. Equation 12 can be rewritten to get the Michaelis-Menten equation:
The equation 13 represents the typical Michaelis-Menten equation when the substrate concentration is far higher than the enzyme.
Derive the Michaelis-Menten equation. Convert the derived equation to a linear form.
1. (15 points) Give the Michaelis-Menten equation and define each term in it (no need to derive the equation). Does this equation apply to all enzymes? If not, to which kind does it not apply?
The kinetics of enzyme catalyzed reactions can be described the Michaelis-Menten equation and the Eadie-Hofstee equation as shown below: V0 = (-Km) V0 / [S] + Vmax a). Please derive the Eadie-Hofstee equation starting from the Michaelis-Menten equation. b). The Vmax and Km of the enzyme catalyzed reaction can be derived from a plot of V0 versus V0/[S]. Please draw one of these plots and explain how do you use it to derive Vmax and Km. c). Please draw a...
(5) The Michaelis-Menten equation describes the following simplistic pathway Km (a) State each of the assumptions on which the Michaelis-Menten equation is based. (b) Derive the rate law for this process
The equation that describes the above Michaelis-Menten curve: Vo TS]+K Vmax [S] Michaelis-Menten Equation Lineweaver and Burke manipulated the Michaelis-Menten equation to yield: Ko V I S Vmax [S] Lineweaver-Burke Equation Linewenver Burke Equation If you plot 1/ V. vs. 1/[S], you get the following Lineweaver-Burke plot: 1/V. Slope = km/Vmax Intercept = -1/KM -Intercept = 1/Vmax 1/[S] Which is easier to calculate values for Km and Vmax, using the linear (y=mx+b) Lineweaver-Burke Plot or the Michaelis-Menten curve?
For substrate inhibition, one can write the following equations. Derive the Michaelis-Menten equation using the simplified protocol described in the lab. E + S ↔ ES-->E + P ES + S-->ES2
1. Show, using the Michaelis-Menten equation, that when [S] >>> Km, vo = Vmax. Show, using the M-M equation that when [S] <<<Km, vo =[S][Et]kcat/Km. 2. What is Vmax? Provide both a mathematical and written description of Vmax? How can Vmax be experimentally altered? How can we use Vmax to determine the turnover number (kcat) of an enzyme-catalyzed reaction? What is the major challenge of determining Vmax from an Michaelis-Menten plot?
1)Derivation of the Michaelis -Menten equation. I want you to show every single step
4. Basic concepts of Michaelis-Menten kinetics. The Michaelis-Menten equation is expression of the relationship between the initial velocity, Vo, of an enzymatic reaction and substrate concentration, [S]. There are three conditions that are useful for simplifying the Michaelis-Menten equation: [S] <<Km; [S] = Km; [S] >> Km. Match each condition with the statement(s) that describe it. TV, Vmox[S] Vo =Vmax m . V Vo - Vmax [S] Km +[S] V. (um/min) max [S] (mm) (a) Doubling [S] will almost double...
The Michaelis-Menten equation is often used to describe the kinetic characteristics of an enzyme-catalyzed reaction. S Where v is the velocity or rate, Vmax is the maximum velocity, Km is the +IST Michaelis- Menten constant, and I5 s the substrate concentration. K + S v (uM/min) a) A graph of the Michaelis-Menten equation is a plot of a reaction's initial velocity (Vo) at different substrate concentrations ([S]) 300 Vmax 250 1/2 Vmax First, move the line labeled "Vmax to a...