A partial diploid E. coli strain does not express lacZ either in the presence or in...
A partial diploid E. coli strain does not express lacZ either in the presence or in the absence of lactose. Which of the following genotypes are consistent with this phenotype?
A. ISO+Z+/F'I-OCZ+
B. I-O+Z-/F'I-OCZ+
C. ISO+Z+/F'I-OCZ-
D. I+O+Z+/F'I-OCZ+
E. ISO+Z-/F'I-OCZ+
Homework Answers
- LAC operon of E. coli is an example of inducible gene expression system. Allolactose acts as inducer molecule in lac operon.
- Lac i represents the repressor and is under a separate promoter and not under lac promoter control.
- Lactose acts as inducer, which on binding to repressor, prevents it to bind to the operon and induces expression.
- When there is low glucose concentration, high levels of cAMP are generated that binds to CAP, promoting transcription initiation of lac operon genes.
- Lac i mutation is called super-suppressor, Lac is.
- This makes the repressor insensitive to the inducer.
- The repressor binds to the operator site.
- If there is mutation in repressor gene, repressor is not produced and expression continues with or without inducer.
- If there is mutation in the operator making it O-, the repressor is unable to bind, and transcription occurs even in absence of inducer. However, in merodiploid cell the operator is functional or O+. Thus, trans acting repressor can bind to the functional operator.
- Mutant Oc operator is constitutive cis- dominant. The repressor cannot bind to this operator and thus, for cis-acting genes, there will be continuous transcription, even in absence of inducer.
A. ISO+Z+/F'I-OCZ+: From partially diploid merozygote, for I-, lacZ will be expressed
B. I-O+Z-/F'I-OCZ+: I-= repressor absent, lac Z will be expressed even in absence of lactose
C. ISO+Z+/F'I-OCZ-: Due to the expression of super repressor, lac Z will not be expressed event in presence of lactose. From partially diploid merozygote, for I-, there is z-. So lac z will not be expressed.
D. I+O+Z+/F'I-OCZ+: From partially diploid merozygote, for I-, lacZ will be expressed
E. ISO+Z-/F'I-OCZ+: From partially diploid merozygote, for I-, lacZ will be expressed
Answer: C
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A partial diploid E. coli strain does not express lacZ either in
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Note whether in the following strains of E. coli,
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(A) Abundant in both the presence and absence of lactose
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