an object 3.0 cm high is placed 20.0 cm from a concave lens with a focal length of 8.0 cm. What is the height of the image?
an object 3.0 cm high is placed 20.0 cm from a concave lens with a focal...
An object is placed 20 cm from a converging lens with focal length 15 cm. A concave mirror with focal length 10 cm is located 75 cm to the right of the lens asshown in the figure. Note: The figure is not drawn to scale. A)Determine the location of the final image.B)If the height of the object is 1.0 cm, what is the height of the image?thanks!
1. A 4.00-cm tall object is placed a distance of 48 cm from a concave mirror having a focal length of 16cm. Determine the image distance and the image size. 2. A 4.00-cm tall object is placed a distance of 8 cm from a concave mirror having a focal length of 16cm. Determine the image distance and the image size. 3. Determine the image distance and image height for a 5.00-cm tall object. placed 30.0 cm Infront of from a convex mirror...
7. An object is placed 25.0 cm cm in front of concave lens of focal length -40.0 cm. What is the magnification of the image?
1. A 5.0 cm high object is placed 10.0 cm from a converging lens of focal length 25.0 cm. What is the height of the image formed by the lens? a. 1.67 cm b. 8.35 cm c. 5.38 cm d. 3.85 cm 2. A 2.0 cm tall object is 30.0 cm in front of a diverging lens of focal length 15.0 cm. What is the magnification produced by the lens? a. 0.23 b. 0.33 c. 1.0 d. 0.25
A converging lens of focal length 20.0 cm is separated by 50.0 cm from a converging lens of focal length 5.00 cm. a) Find the position of the final image of an object placed 42.0 cm in front of the first lens. Solve graphically and mathematically. b) If the height of the object is 2.00 cm, what is the height of the final image? c) Is the final image real or virtual? Is it inverted or upright?
A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm height cm Is the image inverted or upright? O upright inverted Is the image real or virtual? Oreal virtual
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
A 1.00-cm-high object is placed 3.25 cm to the left of a converging lens of focal length 7.15 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.
an object is placed 30.0 cm from a concave lens. If a virtual image appears 10.0 cm from the lens on the same side as the object what is the focal length of the lens? explain
An object arrow 2 cm high is placed 20 cm from a converging lens of focal length of 10 cm. Find a) The location of the final image, b) the nature of image, c) the magnification and height of the image. d)Draw a ray diagram of the image formation