Question

9. How do the molecular geometry of the molecule IF5 and PF5 differ? A. In IF5,...

9. How do the molecular geometry of the molecule IF5 and PF5 differ?

A. In IF5, there is a lone pair of electrons on iodine where as in PF5 there are no lone pairs on phosphorus. As a result, the molecular shape of IF5 is square pyramidal and PF5 is trigonal bipyramidal.

B. In PF5, there is a lone pair of electrons on phosphorus where as in IF5 there are no lone pairs on iodine. As a result, the molecular shape of PF5 is square pyramidal and IF5 is trigonal bipyramidal.

C. In IF5, there is a lone pair of electrons on iodine where as in PF5 there are no lone pairs on phosphorus. As a result, the molecular shape of IF5 is octahedral and PF5 is trigonal bipyramidal.

10. What are the bond angle formed by the central atom P and two of the equatorial fluorine’s in the molecular geometry of PF5 ? A. 90° B. 120° C. 109.5°

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Answer #1

9) Option A is correct.

IF5 ------- The valence of Iodine is 7. Iodine is sp3d2 hybridized. One lone pair on Iodine and 5 bond pairs present.

The molecule shape is square pyramid according to VSEPR theory

PF5 ------- The valence of Iodine is 5. Iodine is sp3d hybridized. No lone pair ,5 bond pairs present

The molecule shape is trigonal bipyramid.

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10) Option B is correct.

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