Question

Here is an example you can use: the mean of a random sample is 15 and...

Here is an example you can use: the mean of a random sample is 15 and the margin of error figured for the 95% confidence interval is 3.5

1. What does the margin of error imply?

2. Estimate population mean using given information above. Interpret your interval estimate for population mean.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution:

Given ,

sample mean = 15

Margin of error = 3.5

confidence level = c = 95%

1.

We are 95% confident that the population mean is within 3.5 of the 15.

2.

Confidence interval for mean is given by

sample mean margin of error

15 3.5

(15 - 3.5 , 15 + 3.5)

(11.5 , 18.5)

The 95% confidence interval for the population mean is (11.5 , 18.5)

Add a comment
Know the answer?
Add Answer to:
Here is an example you can use: the mean of a random sample is 15 and...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Here is an example with steps you can follow: sample size n=9, sample mean=80, sample standard...

    Here is an example with steps you can follow: sample size n=9, sample mean=80, sample standard deviation s=25 (population standard deviation is not known) Estimate confidence interval for population mean with confidence level 90%. Confidence Interval = Sample Mean ± Margin of Error Margin of Error = (t-value)×s/√n t-value should be taken from Appendix Table IV. For n=9 df=n-1=9-1=8 For Confidence Level 90% a = 1 - 0.90 = 0.10, a/2 = 0.10/2 = 0.05 So, we are looking for...

  • Use the t-distribution to find a confidence interval for a mean u given the relevant sample...

    Use the t-distribution to find a confidence interval for a mean u given the relevant sample results. Give the best point estimate for u, the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed. A 95% confidence interval for u using the sample results I = 10.5,5 = 6.9, and n = 30 Round your answer for the point estimate to one decimal place, and your...

  • In a random sample of six mobile devices, the mean repair cost was $70.00 and the...

    In a random sample of six mobile devices, the mean repair cost was $70.00 and the standard deviation was $11.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval forte population mean. Interpret the results. The 95% confidence interval for the population m ean μ is (DO). Round to two decimal places as needed.) The margin of error is s (Round to two decimal places as needed.)...

  • In a random sample of 17 people, the mean commute time to work was 30.7 minutes and the standard deviation was 7.3 minutes

    In a random sample of 17 people, the mean commute time to work was 30.7 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 95% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results. The confidence interval for the population mean μ is  _______ . The margin of error of μ is _______ .Interpret the results A. With 96% confidence, it can...

  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence ntervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals A random sample of 45 home theater systems has a mean price of $138.00. Assume the population standard deviation is 516.40. Construct a 90% confidence interval for the population mean. The 90% confidence interval...

  • In a random sample of six mobile​ devices, the mean repair cost was ​$80.00 and the...

    In a random sample of six mobile​ devices, the mean repair cost was ​$80.00 and the standard deviation was ​$12.00. Assume the population is normally distributed and use a​ t-distribution to find the margin of error and construct a 95​% confidence interval for the population mean. Interpret the results. The 95​% confidence interval for the population mean mu is

  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$127.00. Assume the population standard deviation is ​$19.20. Construct a​ 90% confidence interval for the population mean. The​ 90% confidence interval...

  • AM You are given the sample mean and the population standard deviation. Use this information to...

    AM You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 35 home theater systems has a mean price of $144.00. Assume the population standard deviation is $15.60. Construct a 90% confidence interval for the population mean. The 90% confidence...

  • For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c)...

    For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c) below. Assume that x is normally distributed x= 27, n=9, 0 = 6 a. Find a 95% confidence interval for the population mean The 95% confidence interval is from to (Round to two decimal places as needed.) b. Identify and interpret the margin of error. The margin of error is (Round to two decimal places as needed.) Interpret the margin of error. Choose the...

  • For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c)...

    For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c) below. x= 23, n= 36, 3 = 3 a. Find a 95% confidence interval for the population mean. The 95% confidence interval is from to (Round to two decimal places as needed.) b. Identify and interpret the margin of error. The margin of error is (Round to two decimal places as needed.) Interpret the margin of error. Choose the correct answer below. O A....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT