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The mean is 44.8 and the standard deviation is 16.2 for a population. Using the Central...

The mean is 44.8 and the standard deviation is 16.2 for a population. Using the Central Limit Theorem, what is the variance of the distribution of sample means for samples of size 50? Please round your answer to the nearest tenth. Note that the correct answer will be evaluated based on the full-precision result you would obtain using Excel.

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Answer #1

Answer:

Let X' denotes the sample mean for a sample of size n = 50.

Var(X') = 16.2^2 / 50

= 5.2488

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