Suppose x has a distribution with μ = 40 and σ = 19.
Find P(36 ≤ x ≤ 41).
for normal distribution z score =(X-μ)/σx | |
here mean= μ= | 40 |
std deviation =σ= | 19.000 |
probability =P(36<X<41)=P((36-40)/19)<Z<(41-40)/19)=P(-0.21<Z<0.05)=0.5199-0.4168=0.1031 |
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