Question

Suppose that the weight of a Beagle varies Normally with mean 26 pounds and standard deviation...

Suppose that the weight of a Beagle varies Normally with mean 26 pounds and standard deviation 3. What is the probability that a randomly selected Beagle weighs between 20 and 28 pounds?

BE CAREFUL: YOU MUST USE THE TABLE TO GET THIS ANSWER CORRECT. Round your z-scores to two decimal places before using the table.  

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Answer #1

Solution :

Given that ,

mean = = 26

standard deviation = = 3

P(20< x <28 ) = P[(20-26) /3 < (x - ) / < (28-20) /3 )]

= P( -2< Z < 2.67)

= P(Z <2.67 ) - P(Z < -2)

Using z table   

= 0.9962-0.0228

probability= 0.9734

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