If the yeast genomic insert is 1000 bp, will the PCR gnerate the 100 ng needed...
If the yeast genomic insert is 1000 bp, will the PCR gnerate the 100 ng needed for a sequencing reaction? (Use: average molecular weight of a base pair = 650 g/mole and Avogadro's number.)
Homework Answers
PCR is a technique used to amplifya given genomic insert into multiple copies of with the help of DNA Polymerase, Nitrogen Bases, Primers in a Reaction Buffer.
In the above question Yeast Genome Insert is having 1000 bp and we requires 100ng, but Molecular Weight of single base pair is 650 g/mole. WHICH IS HIGHER COMPARED TO THE REQUIRED.(i.e 100ng)
Note : 1 gram = 10^9.
So, answer is that PCR can't generate 100ng.
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If the yeast genomic insert is 1000 bp, will the PCR gnerate the
100 ng needed...
If the yeast genomic insert is 1000 bp, will the PCR gnerate the 100 ng needed for a sequencing r...
If the yeast genomic insert is 1000 bp, will the PCR gnerate the 100 ng needed for a sequencing reaction? (Use: average molecular weight of a base pair = 650 g/mole and Avogadro's number.)
2. PCR amplification of the TAS2R38 gene a. The number of copies of the 303 bp sequence grows exp...
2. PCR amplification of the TAS2R38 gene a. The number of copies of the 303 bp sequence grows exponentially (1-2-4-8-etc) after each cycle. The number of cycles we used is on page 97. What is the number of copies of the 303 bp fragment that will theoretically be present at the end of our reaction? b. Denaturation of the 303 bp segment of the TAS2R38 gene is a critical first step in the PCR perties of a DNA segment that...
General Chemistry Workshop 9: The Mole The mole is the unit of measurement for an amount...
General Chemistry Workshop 9: The Mole The mole is the unit of measurement for an amount in chemistry and physics. It is defined as the amount of sample that contains as many items as there are atoms in 12 grams of carbon 12 ( isotope). The number of items in 1 mole is called the Avogadro's number NA - 6.022141 x 100 1/mol Mole in science, just like a dozen in our everyday life, allows us to quickly count or...
12) What is the sum of the cofficients when the following equation is balianced using the...
12) What is the sum of the cofficients when the following equation is balianced using the lowest whole-numbered coefficients? H20(gl A) 10 B) 12 C) 19 D) 22 13) Which contains Avogadro's number of formula units? A) 36.5 g of a 8) 36.5 g of Ch C) 36.5 g of H of these 14) What is the molar mass of aspartic acid, C404H7N? 70 g/mol gm)1g/mol A) 43 g/mol S) A compound responsible for the odor ofgarlic has a molecular...
5) How many moles of hydrogen gas are needed to react with oxygen to form one...
5) How many moles of hydrogen gas are needed to react with oxygen to form one mole of 5) water? 2H2(8) + O268) - 2H20(1) A) 4 mol B) 1 mol C) 2 mol D) 0.5 mol E) 6 mol 6) Incomplete combustion occurs when there is insufficient oxygen to react with a compound. The suffocating gas carbon monoxide is a product of incomplete combustion. How many moles of oxygen gas are required for the complete combustion of 11.0 moles...
En (2 points) You isolated your mitochondrial DNA in Part I. In step 6, you discard...
En (2 points) You isolated your mitochondrial DNA in Part I. In step 6, you discard the supernatant, but keep the pellet. In step 15, you discard the pellet, but keep the supernatant. Explain why the pattern is different between the two steps and the consequence of mixing up these two steps. Procedure Part 1: mt DNA Isolation from your cheek cells. Lysis solution is used to breakdown the cells in this step, you will isolate MEONA from cheek cells....
2. How many mL of 0.100M NaOH would you need to titrate if you measured out...
2. How many mL of 0.100M NaOH would you need to titrate if you measured out 0.120 g of oxalic acid? Must show calculation. (5 pts) lying an unknown acid Objective: Identify an unknown diprotic acid by determining its molecular weight. Introduction: A diprotic acid is an acid that yields two H ions per acid molecule. Therefore, two moles of NaOH are need to react with every one mole of diprotic acid. The net reaction of a diprotic acid, H:X,...
Unknown acid 2 6. Complete the following table. Trial 1 Trial 2 Trial 3 Mass of...
Unknown acid 2 6. Complete the following table. Trial 1 Trial 2 Trial 3 Mass of unknown (8) 0.175 0.120 0.122 Initial buret reading (mL) 0.00 22.37 0.00 Final buret reading (mL) 22.37 44.85 22.83 Volume of NaOH added (mL) 22.37 22.48 22.83 We will assume that the data collected for the first trial is not accurate. 7. What is the average mass of unknown acid for Trials 2 and 3? (Must show calculations) 8. What is the average volume...
please complete the questions has not answering with clarification of the answer to any page Name...
please complete the questions has not answering with
clarification of the answer to any page
Name Lab Section _Date The Mole Concept and Atomic Weights The purpose of this activity is to better understand the concepts of relative atomic mass, counting by weighing and the mole. Percent composition and average atomic mass are included. Part I. Relative Atomic Masses and the Mole - Early Method When John Dalton proposed his atomic theory, he stated that the atoms of each element...
The titrant solution is on the last page. All the info needed is on the pages provided. paticularly on t...
The
titrant solution is on the last page.
All
the info needed is on the pages provided. paticularly on the last
page
Table 1: Standardization Data Trial 3 Trial 1 Trial 2 O.47644 0.4701 25. mL ou779 12.7mL 25. mL 12.4 mL Mass of KHP Initial burette reading 2.7mL 37,Sm 2.4m Final burette reading 12.7mL Volume of base used Data Analysis: 1. Write a balanced molecular equation (with phases, of course) for the reaction between the KHP and the titrant...
2. PCR amplification of the TAS2R38 gene a. The number of copies of the 303 bp sequence grows exponentially (1-2-4-8-etc) after each cycle. The number of cycles we used is on page 97. What is the number of copies of the 303 bp fragment that will theoretically be present at the end of our reaction? b. Denaturation of the 303 bp segment of the TAS2R38 gene is a critical first step in the PCR perties of a DNA segment that...
General Chemistry Workshop 9: The Mole The mole is the unit of measurement for an amount in chemistry and physics. It is defined as the amount of sample that contains as many items as there are atoms in 12 grams of carbon 12 ( isotope). The number of items in 1 mole is called the Avogadro's number NA - 6.022141 x 100 1/mol Mole in science, just like a dozen in our everyday life, allows us to quickly count or...
12) What is the sum of the cofficients when the following equation is balianced using the lowest whole-numbered coefficients? H20(gl A) 10 B) 12 C) 19 D) 22 13) Which contains Avogadro's number of formula units? A) 36.5 g of a 8) 36.5 g of Ch C) 36.5 g of H of these 14) What is the molar mass of aspartic acid, C404H7N? 70 g/mol gm)1g/mol A) 43 g/mol S) A compound responsible for the odor ofgarlic has a molecular...
5) How many moles of hydrogen gas are needed to react with oxygen to form one mole of 5) water? 2H2(8) + O268) - 2H20(1) A) 4 mol B) 1 mol C) 2 mol D) 0.5 mol E) 6 mol 6) Incomplete combustion occurs when there is insufficient oxygen to react with a compound. The suffocating gas carbon monoxide is a product of incomplete combustion. How many moles of oxygen gas are required for the complete combustion of 11.0 moles...
En (2 points) You isolated your mitochondrial DNA in Part I. In step 6, you discard the supernatant, but keep the pellet. In step 15, you discard the pellet, but keep the supernatant. Explain why the pattern is different between the two steps and the consequence of mixing up these two steps. Procedure Part 1: mt DNA Isolation from your cheek cells. Lysis solution is used to breakdown the cells in this step, you will isolate MEONA from cheek cells....
2. How many mL of 0.100M NaOH would you need to titrate if you measured out 0.120 g of oxalic acid? Must show calculation. (5 pts) lying an unknown acid Objective: Identify an unknown diprotic acid by determining its molecular weight. Introduction: A diprotic acid is an acid that yields two H ions per acid molecule. Therefore, two moles of NaOH are need to react with every one mole of diprotic acid. The net reaction of a diprotic acid, H:X,...
Unknown acid 2 6. Complete the following table. Trial 1 Trial 2 Trial 3 Mass of unknown (8) 0.175 0.120 0.122 Initial buret reading (mL) 0.00 22.37 0.00 Final buret reading (mL) 22.37 44.85 22.83 Volume of NaOH added (mL) 22.37 22.48 22.83 We will assume that the data collected for the first trial is not accurate. 7. What is the average mass of unknown acid for Trials 2 and 3? (Must show calculations) 8. What is the average volume...
please complete the questions has not answering with
clarification of the answer to any page
Name Lab Section _Date The Mole Concept and Atomic Weights The purpose of this activity is to better understand the concepts of relative atomic mass, counting by weighing and the mole. Percent composition and average atomic mass are included. Part I. Relative Atomic Masses and the Mole - Early Method When John Dalton proposed his atomic theory, he stated that the atoms of each element...
The
titrant solution is on the last page.
All
the info needed is on the pages provided. paticularly on the last
page
Table 1: Standardization Data Trial 3 Trial 1 Trial 2 O.47644 0.4701 25. mL ou779 12.7mL 25. mL 12.4 mL Mass of KHP Initial burette reading 2.7mL 37,Sm 2.4m Final burette reading 12.7mL Volume of base used Data Analysis: 1. Write a balanced molecular equation (with phases, of course) for the reaction between the KHP and the titrant...
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