5) How many moles of hydrogen gas are needed to react with oxygen to form one...
31). 31) To convert a given number of moles into the number of atoms, one would multiply by which of the following factors? A) 1.66 x 10-24 atoms/1 mol B) 1 mol/6.022 x 1023 atoms C) molar mass D) 6.022 x 1023 atoms/1 mol E) 1 mol/1.66 x 10-24 atoms 32) 32) How many atoms of sulfur are present in a 155 g sample of sulfur? [Molar mass: S, 32.06 g/mol] A) 6.02 x 1023 atoms B) 2.91 x 1023...
Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) 1) One mole of any substance contains Avogadro's number of particles of that substance. What is the numerical value of Avogadro's number? A) 12.01 23 Avagrans t Male aton 6022 x1o atums B) 6.022 x 1023 C) 6.022 x 10-23 D) 1.661 x10-24 E) 1.00 x10-14 2) What is the mass of 4.00 moles of helium, the gas commonly used to fill...
5) Choose the best classification of the reaction represented by the following equation: Pb(NO3)2(ay)+CaClg(ay)-PbCl20)+ Ca(NO3)2(a) A) decomposition B) precipitation C) oxidation-reduction D) acid-base E) combustion 5) 6) 6) Choose the best classification of the reaction represented by the following equation: HBr(ay)+ KOH(ag)KBr(ag) + H20( A) acid-base B) precipitation C) combustion D) combination E) decomposition 7) 7) Magnesium hydroxide, Mg(OH)2, as "Milk of Magnesia" can be used to neutralize excess stomach acid, represented by HCl(ag) according to the chemical equation below....
m105%20Makeup%20Exam%20(2).pdf 31) 31) To convert a given number of moles into the number of atoms, one would multiply by which of the following factors? A) 1.66 x 10-24 atoms/I mol B) 1 mol/6.022 1023 atoms C) molar mass D) 6.022 * 1023 atoms/1 mol E) 1 mol/1.66 x 10-24 atoms 3 2) 32) How many atoms of sulfur are present in a 155 g sample of sulfur? [Molar mass: S 32.06 g/mol) A) 6.02 x 1023 atoms B) 2.91 x...
7) Magnesium hydroxide, Mg(OH)2, as "Milk of Magnesia" can be used to neutralize excess stomach acid, represented by HCl(ag) according to the chemical equation below. Mg(OH)2(s)+2HCI (ag)-MgCl2(ag)+ 2H20( When 5.00 g of HCl are combined with an excess of Mg(OH)2, what mass of MgCl2 can be produced? [Molar masses: H, 1.01 g/mol; O, 16.00 g/mol; Mg, 24.31 g/mol; Cl, 35.45 g/mol] A) 2.50 g E) 70.5 g D) 6.53 g C) 0.957 g B) 13.1 g 8) What is the...
1. Choose the correct answer(s) to complete the following statement: One mole of oxygen (O2) gas is equivalent to _____________________. I. 6.022 × 1023 molecules of oxygen II. 6.022 × 1023 atoms of oxygen III. one mole of oxygen atoms IV. two moles of oxygen atoms 2. 50.0 g of Cl2 contains ________ mol Cl2. a. 0.705 b.1.41 c. 4.24 × 1023 d. 1775 e. 50.0 3. The number of grams in 0.350 mol of Na is a. 11.0. b....
39) What property of liquids explains the formation of leaves? A) surface tension B) adhesion C) viscosity D) vapor pressure E) None of the choices are correct. mation of spherical water droplets on green 3 9) - um at constant pressure and temperature has the volume 40) 40) A balloon containing helium at constant pres doubled by adding a more helium. Which ' adding a more helium. Which statement(s) isare) TRUE? A) The number of moles of helium doubled. B)...
How many moles of oxygen (O2) are needed to react with 12.50 moles of C2H2 in the reaction? 2C2H2 + 5O2 ⟶4 CO2 + 2 H2O C2H2 = 26.038 g/mol; O2 = 31.998 g/mol; CO2 = 44.01 g/mol; H2O = 18.01 g/mol Group of answer choices 42.9 g 31.3 23.7 5.00
One mole of oxygen molecule contains how many atoms of oxygen? Show work. Select one: a. 6.022 x 1023 b. 1.204 x 1024 c. 1.6021 x 10−19 d. 1.6021 x 1019
17-21 17) Consider the following reaction. How many moles of oxygen are required to produce 10.0 moes of 17) water? Assume that there is excess C3H7SH present. C3H7SH)+602(g) 3CO2(g)+S02(g)+4 H20(g) A) 15.0 moles O2 B) 6.67 moles O2 C) 10.0 moles O2 D) 40.0 moles O2 E) 250 moles O2 18) How many molecules of HCl are formed when 80.0 g of water reacts according to the following) balanced reaction? Assume excess ICl3. A) 4.46 1024 molecules HCI B) 536...