a)
During polymerase chain reaction (PCR), the number of double stranded DNA pieces is doubled in each cycle.
Therefore, after n cycles, total number of the copies of double stranded DNA would be 2n
So after 40 cycles, total number of 303 bp long template would be 240 copies= 1,099,511,627,776 copies
b)
To facilitate the separation of double stranded DNA into single stranded DNA, the initial denaturation step is carried out at the beginning of PCR. Initial denaturation steps aims to complete denaturation of the template DNA.
The initial denaturation step is commonly performed at 94–98°C for 1–5 minutes.
The temperature and time used for initial denaturation steps in PCR is greatly influence by the following two properties of template DNA
1) Nature of the template DNA: whether the template is a mammalian genomic DNA or a plasmid or a PCR product i.e. based on the nature of the template, the temperature for initial denaturation may vary. For example, as the mammalian genomic DNA is more complex and larger in size, it require longer incubation period than plasmid for initial denaturation.
2) GC content of the template DNA:
Template DNA with high GC content require higher temperature and longer incubation for initial denaturation compared to the DNA template having less GC content.
c) Suggestion
Generally the length of the PCR primers are 17- 30 bases. The bases in PCR primers may be counted i.e the number of A, T, G and C may be counted and as per the formula given in the question the Tm of the PCR primer (Detail of PCR primer is not available in the question) would be calculated.
2. PCR amplification of the TAS2R38 gene a. The number of copies of the 303 bp sequence grows exp...
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