Question

   Write the electron configurations for each of the following elements and its ions:

(a) Ti
(b) Ti2+

(c) Ti3+
(d) Ti4+

Answer 1

1)

Number of electron in Ti = 22

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d2 4s2

Answer: 1s2 2s2 2p6 3s2 3p6 3d2 4s2

2)

Number of electron in Ti = 22

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d2 4s2

Since charge on Ti is +2

So, we need to remove 2 electrons

Electrons are always removed from highest number orbital

Removing 2 electron from 4s

Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d2

Answer: 1s2 2s2 2p6 3s2 3p6 3d2

3)

Number of electron in Ti = 22

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d2 4s2

Since charge on Ti is +3

So, we need to remove 3 electrons

Electrons are always removed from highest number orbital

Removing 2 electron from 4s

Removing 1 electron from 3d

Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d1

Answer: 1s2 2s2 2p6 3s2 3p6 3d1

4)

Number of electron in Ti = 22

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d2 4s2

Since charge on Ti is +4

So, we need to remove 4 electrons

Electrons are always removed from highest number orbital

Removing 2 electron from 4s

Removing 2 electron from 3d

Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6

Answer: 1s2 2s2 2p6 3s2 3p6