[12] For this set of parents, is it possible to draw conclusions about the genotype counts...
[12] For this set of parents, is it possible to draw conclusions about the genotype counts from examining the phenotypes? Why or why not? Use counts from one of your bb vs Bb data runs as part of your discussion.
|
Punnett Square |
Male |
||
|
Female |
Alleles/Genes |
B |
b |
|
b |
Bb |
bb |
|
|
b |
Bb |
bb |
|
Homework Answers
It is not possible to draw conclusion from the given punnett square. This is because, in the given punnett square only the genotype of the individuals is given, but information about the alleles is missing. Without knowing about the allele, we can not determine the phenotype of the offspring.
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[12] For this set of parents, is it possible to draw conclusions
about the genotype counts...
I need help with number 12 giving the information in the graph [12] For this set...
I need help with number 12 giving the information in the graph [12] For this set of parents, is it possible to draw conclusions about the genotype counts from examining the phenotypes? Why or why not? Use counts from one of your bb vs Bb data runs as part of your discussion. Procedure I - Part C - Baby bugs when parents are bb and Bb Data Table - Enter your Baby Bug Counts from each data run Data Run...
USING THE CompleteD the Punnett square below when the parents are BB and bb. Punnett Square...
USING THE CompleteD the Punnett square below when the parents are BB and bb. Punnett Square Male Female Alleles/Genes b b B Bb Bb B Bb Bb [2] Describe your baby bug results from this data run in terms of genotypes and phenotypes.
1. What would be the phenotype for each of the following birds, including their gender? Color...
1. What would be the phenotype for each of the following birds, including their gender? Color Gender Bb ZZi: - bb ZiZi: - BB ZZ: - bb ZW: - Bb ZiW: - 2. Using the phenotypes of the parents and of the progeny given in table 1, determine the genotype of each parent in the first nest. Male Female 3. Using the phenotypes of the parents and of the progeny given in table 2, determine the genotype of each parent...
Analyzing Genetic Data A. ABO Blood Group The human ABO blood group is an example of...
Analyzing Genetic Data A. ABO Blood Group The human ABO blood group is an example of how three alleles that control a trait may interact. In this case, two of the alleles are codominant and one is recessive to the other two. The table below lists the phenotypic and genotypic data for this trait. Blood Type Phenotype Type A Type B Type AB | Type 0 Possible Genotype Ilori Pori | IAI 1. List the three alleles that control expression...
I did 1-5 but confused on the rest LAB EXERCISE 4.1 continued Name 6 Remember that...
I did 1-5 but confused on the rest
LAB EXERCISE 4.1 continued Name 6 Remember that the ability to taste PTC is dominant to the inability. Two normally pigmented taster parents have an albino, taster son and a non-taster daughter with normal pigmentation. Using A and Tand a and t for the dominant and recessive alleles, respectively, create a Punnett square for two traits, as shown on pages 71-73 in the section "Transmission of Autosomal Traits: Two at a Time."...
Nameindulia Los Drosophila Genetics Predictions-L113 (20 pts.) Part I. Meiosis and Punnett Squares Remember, whenever you...
Nameindulia Los Drosophila Genetics Predictions-L113 (20 pts.) Part I. Meiosis and Punnett Squares Remember, whenever you use Punnett Squares to solve genetics problems, be sure you are completing each of the following steps: 1) Identify the genotypes of the parents. 2) For the specific traits of interest, figure out what kinds of haploid gametes each parent can make. In each gamete, there should be one allele for each trait of interest. If there is more than one trait, make sure...
Sex Linked inheritance: Set up your own mating between two flies but at least one parent...
Sex Linked inheritance: Set up your own mating between two flies but at least one parent must have a white allele in it, and present the Punnett square, genotype and phenotypes of both parents and the offspring of this cross. Remember to show the alleles on the X and/or Y chromosomes. W cannot be used for white and for the wild at the same time. Subscripts must be used. i.e Xw+Y x Xw+Xw 1 Xw+Y : 1 XwY : 1 Xw+Xw+ :...
Now, Danielle wants to know how her twins could look so diffe skin and Michael Jr....
Now, Danielle wants to know how her twins could look so diffe skin and Michael Jr. having dark skin. First, Danielle neede types of twins. Identical twins have exactly the same genes, since in a developing embryo splits into two embryos. Part III: Why do the twins look so different? er twins could look so different, with Michelle having light dark skin. First, Danielle needs to understand that there are two exactly the same genes, since identical twins originate when...
BIO 142 Test X 9) Curly hair (CC) is incompletely dominant over straight hair (ce), therefore the heterozygous genotype (Ce) produces wavy hair (Ce), Set up the Punnet square and cross a mother with...
BIO 142 Test X 9) Curly hair (CC) is incompletely dominant over straight hair (ce), therefore the heterozygous genotype (Ce) produces wavy hair (Ce), Set up the Punnet square and cross a mother with wavy hair with a man with wavy hair. (5 points) What is the percentage of different phenotypes of their children? Show your works. Female Genotype: Genotype ratio Phenotype ratio: Male Genotype: 10) Cross a father with blood type AO and a mother with BO blood type....
need help with 1-3 1. Corgi coats exist in two different colors: tan and black. Imagine...
need help with 1-3
1. Corgi coats exist in two different colors: tan and black. Imagine that the alleles for the tan coat are dominant to the alleles for the black coat. Draw a Punnett square resulting from a cross between two heterozygous tan corgis. a. Label the gametes from each parent with the probability of passing each allele b. What is the probability that a corgi will have a recessive genotype from the two parents? 2. If a corgi...
Analyzing Genetic Data A. ABO Blood Group The human ABO blood group is an example of how three alleles that control a trait may interact. In this case, two of the alleles are codominant and one is recessive to the other two. The table below lists the phenotypic and genotypic data for this trait. Blood Type Phenotype Type A Type B Type AB | Type 0 Possible Genotype Ilori Pori | IAI 1. List the three alleles that control expression...
I did 1-5 but confused on the rest
LAB EXERCISE 4.1 continued Name 6 Remember that the ability to taste PTC is dominant to the inability. Two normally pigmented taster parents have an albino, taster son and a non-taster daughter with normal pigmentation. Using A and Tand a and t for the dominant and recessive alleles, respectively, create a Punnett square for two traits, as shown on pages 71-73 in the section "Transmission of Autosomal Traits: Two at a Time."...
Nameindulia Los Drosophila Genetics Predictions-L113 (20 pts.) Part I. Meiosis and Punnett Squares Remember, whenever you use Punnett Squares to solve genetics problems, be sure you are completing each of the following steps: 1) Identify the genotypes of the parents. 2) For the specific traits of interest, figure out what kinds of haploid gametes each parent can make. In each gamete, there should be one allele for each trait of interest. If there is more than one trait, make sure...
Now, Danielle wants to know how her twins could look so diffe skin and Michael Jr. having dark skin. First, Danielle neede types of twins. Identical twins have exactly the same genes, since in a developing embryo splits into two embryos. Part III: Why do the twins look so different? er twins could look so different, with Michelle having light dark skin. First, Danielle needs to understand that there are two exactly the same genes, since identical twins originate when...
BIO 142 Test X 9) Curly hair (CC) is incompletely dominant over straight hair (ce), therefore the heterozygous genotype (Ce) produces wavy hair (Ce), Set up the Punnet square and cross a mother with wavy hair with a man with wavy hair. (5 points) What is the percentage of different phenotypes of their children? Show your works. Female Genotype: Genotype ratio Phenotype ratio: Male Genotype: 10) Cross a father with blood type AO and a mother with BO blood type....
need help with 1-3
1. Corgi coats exist in two different colors: tan and black. Imagine that the alleles for the tan coat are dominant to the alleles for the black coat. Draw a Punnett square resulting from a cross between two heterozygous tan corgis. a. Label the gametes from each parent with the probability of passing each allele b. What is the probability that a corgi will have a recessive genotype from the two parents? 2. If a corgi...
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