Question

Create a python code named LetterCount with a text file named words.txt that contains at least 100 words in any format - some words on the same line, some alone (this program involves no writing so you should not be erasing this file). Then create a program in the main.py that prompts the user for a file name then iterates through all the letters in words.txt, counting the frequency of each letter, and then printing those numbers at the end to the console. Convert all letters that you read into lower-case and ignore non-letter characters (.isalpha() and .lower() will help here).

Answer 1

'''
Python version : 2.7
Python program to read a text file words.txt and count the frequency of each letter in
the file irrespective of its case
'''

# specify the file name
filename = 'words.txt'

# open a file in read mode
file = open(filename)
# read the entire file and store in contents
contents = file.read()
#close the file
file.close()
# create a dictionary where keys are letters of alpabets and values are its counts in the file
frequency = {}

# loop over each character in contents
for character in contents:
   # if character is an alphabet
   if character.isalpha():
       # convert the character to lower case and check if it is present in the dictionary
       # then increment its frequency by 1
       if character.lower() in frequency:
           frequency[character.lower()] += 1
       else: # else create a new record in dictionary with value 1
           frequency[character.lower()] = 1
          
# get the list of letters in frequency
letters = frequency.keys()
letters.sort() # sort the letters in ascending order

# display the character and their frequency
print('%-20s %-20s' %('Letter','Frequency'))
for letter in letters:  
   print('%-20s %-20d' %(letter,frequency[letter]))

#end of program      

Code Screenshot:

Output:

Input file:

Output: