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A buffer solution was prepared by mixing 0.1M K2HPO2 and 0.1M KH2PO4 (pH 6.64) - calculate...

A buffer solution was prepared by mixing 0.1M K2HPO2 and 0.1M KH2PO4 (pH 6.64) - calculate the ionic strength (I) of the standard phosphate buffer solution

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Answer #1

According to the Henderson-Hasselbulch equation:

pH = pKa + Log[K2HPO4]/[KH2PO4])

i.e. 6.64 = pKa + Log(0.1/0.1)

i.e. pKa = 6.64

i.e. pH = pKa

In the case of pH = pKa, the ionic strength (I) of the buffer solution = 0

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