How far should an object be from a converging lens of focal length 35.0 cm to form a real image 1/4 its size?
How far should an object be from a converging lens of focal length 35.0 cm to...
A converging lens has a focal length of 21 cm. How far from the lens should an object be placed to get a real image with a magnification of 3.4 and a virtual image with a magnification of 3.4? (a) a real image with a magnification of 3.4 cm (b) a virtual Image with a magnification of 3.4 cm
A converging lens has a focal length of 24 cm. How far from the lens should an object be placed to get a real image with a magnification of 2.2 and a virtual image with a magnification of 2.2? a. a real image with a magnification of 2.2 b. a virtual image with a magnification of 2.2
Q4 #4 How far apart are an object and an image formed by a 89-cm-focal-length converging lens if the image is 2.75× larger than the object and is real?
An object is placed 18 cm from the center of a converging lens of focal length 6 cm. 1) What will be the distance of the image from the lens? (cm) 2) What is the magnification of the image? 3) The object is moved. The image is now 10 cm away from the lens. How far is the object from the lens? (cm)
Consider a converging lens whose focal length is 6.95 cm. An object is placed on the axis of the lens at a distance of 13.5 cm from the lens. How far is the object's image from the lens? image distance: cm If it can be determined, is the image real or virtual? cannot be determined real virtual If it can be determined, is the image upright or inverted with respect to the object? cannot be determined inverted upright
How far apart are an object and an image formed by a 46 cm focal-length converging lens if the image is 4.0× larger than the object and is real? answered attempted: .575m, .58m, .241m, .21m, .23m, .205m
A converging lens of focal length 20.0 cm is separated by 50.0 cm from a converging lens of focal length 5.00 cm. a) Find the position of the final image of an object placed 42.0 cm in front of the first lens. Solve graphically and mathematically. b) If the height of the object is 2.00 cm, what is the height of the final image? c) Is the final image real or virtual? Is it inverted or upright?
A small object is placed 25.0 cm from a converging lens of focal length 40.0 cm. The object is to the left of the lens. Where is the image? A- 17cm to the right of the lens B- 25cm to the left of the lens C- 17 cm to the left of the lens D-25 cm to the right of the lens E-67cm to the right of the lens F-67 cm to the left of the lens A small object...
A diverging lens of focal length –30.0 cm is placed 25.0 cm behind a converging lens of focal length 60.0 cm. A real, upright object of height 2.00 cm is placed 20.0 cm in front of the converging lens. (a) Determine the location of the final image. (Clearly state the location of the final image.) (b) Determine the size and the nature of the final image.
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...