Question

what mass of c3h8 would be required to react completely with 16.75 g of oxygen molecule in the following reation?

C3H8(g) + 5O2(g) ==> 3CO2(g) + 4H2O(g)

Answer 1

Answer 2

To answer this question, we need to use stoichiometry, which is the calculation of the amounts of reactants and products in a chemical reaction.

First, we need to balance the equation:

C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(g)

Next, we need to use the balanced equation to convert the given mass of oxygen into the required mass of propane (C3H8):

1 mole of O2 reacts with 1/5 mole of C3H8 (from the balanced equation)

Molar mass of O2 = 32 g/mol

16.75 g of O2 = 16.75 g / 32 g/mol = 0.5234 mol of O2

Therefore, we need 1/5 x 0.5234 mol = 0.1047 mol of C3H8

Molar mass of C3H8 = 44.1 g/mol

Therefore, we need 0.1047 mol x 44.1 g/mol = 4.61 g of C3H8 to react completely with 16.75 g of O2.