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PLEASE USE PYTHON! Thanks! Write the generator function genAccum(seq, fn), which takes in an iterable and...

PLEASE USE PYTHON! Thanks!

Write the generator function genAccum(seq, fn), which takes in an iterable and a function
fn and yields each accumulated value from applying fn to the running total and the next element.
Note: to convert an iterable into an iterator you use iter(iterable)

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Answer #1

Here is the completed code for this problem. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks

Note: Please maintain proper code spacing (indentation), just copy the code part and paste it in your compiler/IDE directly, no modifications required.

#code

#required method
def genAccum(seq, fn):
    #initializing running total to None
    total=None
    #looping through each element in sequence
    for i in seq:
        #if total is None, setting i as total
        if total==None:
            total=i
        #otherwise calling fn passing total and i, storing in total
        else:
            total=fn(total,i)
        #yielding total
        yield total

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