Why would chloroplasts (in solution) placed under the light have a lower absorbance compared to the chloroplasts (in solution) in the dark? What is happening at the molecular level to be showing these results?
The solution will be prepared with: water, DCIP, reaction buffer, and chloroplasts
Please provide a lot of explanation! Thanks!
ANSWER:
H2O + DCIP (oxidised, blue colour) ----light-------> DCIP (reduced, colourless) + 1/2O2
In vivo, the Hill reaction is:
H2O + NADP ----light-------> NADPH + 1/2O2 + H+
Since the oxidized (blue) DCIP becomes in the reduced state in the tube having chloroplasts under the light, it has lower absorbance reading.
There is no effects in the DCIP state that present in tube having chloroplasts (in solution) placed in the dark.
Why would chloroplasts (in solution) placed under the light have a lower absorbance compared to the...
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