Question

I have a test and have no idea how to do any questions similar to these! Please help and show work.

29.) A 10.0-g sample of krypton has a temperature of 25 ∘C at 580 mmHg . What is the volume, in milliliters, of the krypton gas?

Express your answer to three significant figures and include the appropriate units.

10.) Cyclopropane, C3H6, is a general anesthetic. A 4.1 L sample has a pressure of 5.5 atm .

What is the volume, in liters, of the anesthetic given to a patient at a pressure of 1.4 atm with no change in temperature and amount of gas?

Express your answer using two significant figures.

13.) For a certain amount of gas at constant temperature, the pressure and volume have an inverse relationship (Figure 1). This is called Boyle's law:

P1V1=P2V2

In an ideal gas, particles are considered to interact only when they collide, with no loss in energy or speed occurring during the collision. Studying ideal gases allows for simplifications, such as Boyle's law.

A.) A sample of a gas at room temperature occupies a volume of 40.0 L at a pressure of 512 torr. If the pressure changes to 2560 torr , with no change in the temperature or moles of gas, what is the new volume, V2?

Express your answer with the appropriate units.

B.) If the volume of the original sample in Part A (P1 = 512 torr , V1 = 40.0 L ) changes to 80.0 L , without a change in the temperature or moles of gas molecules, what is the new pressure, P2?

Express your answer with the appropriate units.

14.) A gas has a volume of 4.77 L at 0 ∘C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to each of the following, if n and Pdo not change?

A.) 1.88 L

Express your answer to three significant figures in degrees Celsius.

B.) 1170 mL

Express your answer to three significant figures in degrees Celsius.

C.) 10.1 L

Express your answer to three significant figures in degrees Celsius.

D.) 52.3 mL

Express your answer to three significant figures in degrees Celsius.

Answer 1

Molar mass of Kr=83.798 g/mol

Number of moles of Kr= mass of Kr/ molar mass of Kr

Number of moles of Kr=10 g/83.798 g/mol =0.11933 moles

Pressure = 580 mm (one mm=(1/760) atm )

Convert 580 mm to atm

P=(580/760) atm = 0.7631 atm

T=25+273=298 K

(0.7631 atm)*V=(0.11933 moles*0.0821 L atm mol^-1 K^-1*298 K)

V=3.8258470895 L

V=3825.8470895 ml

V= ml