how many milliliters of 1-butanol will be necessary to prepare 0.030 moles of 1-bromobutane. density alcohol...
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many milliliters of 1-butanol will be necessary to prepare 0.030
moles of 1-bromobutane. density alcohol...
how to calculate actual yield in moles and actual yield in grams? 15g + CH,CH,CH,CH,OH 1-butanol...
how to calculate actual yield in moles and actual yield in
grams?
15g
+ CH,CH,CH,CH,OH 1-butanol NaBr + H2SO4 → CH2CH2CH2CH2Br + NaHSO4 + 1,0 sodium sulfuric 1-bromobutane bromide acid 102.9 15.0 g MM: mass: volume: moles: 74.1 9.25 g 11.4 mL 0.125 98.1 23 g 12.5 mL 0.235 137.0 117.1 g (theory) 13.4 mL (theory) 0,125 (theory) 0.145 338 1.84 bp (°C): 117 D (g/mL): 0.81 n20: 1.3991 102 1.28 1.4401
Isopropyl alcohol is mixed with water to produce a 38.0% (v/v) alcohol solution. How many milliliters...
Isopropyl alcohol is mixed with water to produce a 38.0% (v/v) alcohol solution. How many milliliters of each component are present in 875 mL of this solution? Assume that volumes are additive. alcohol: mL water: ml The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. How many grams of sucrose are needed to make 695 mL of a 38.0% (w/v)...
3 part question Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109...
3 part question
Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109 mmol of butanol nd excess acid and sodium bromide. (Note: the stoichiometric relationship between butanol and romobutane is 1:1) Convert the theoretical yield of 1-bromobutane to moles. Convert the moles to mmol. please clearly explain how to do this using the below information with thr correct sig figs Structure for 1-butanol Molecular weight for 1-butanol density for 1-butanol Bonpoint butanol 117.7°C 74.12 gimol 81...
1. A solution of rubbing alcohol is 76.5 % (v/v) isopropanol in water. How many milliliters...
1. A solution of rubbing alcohol is 76.5 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 77.5 mL sample of the rubbing alcohol solution? Express your answer to three significant figures. 2. How many liters of a 3.18 M K2SO4 solution are needed to provide 98.8 g of K2SO4 (molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Express your answer to three significant figures.
1) A solution of rubbing alcohol is 69.0 % (v/v) isopropanol in water. How many milliliters...
1) A solution of rubbing alcohol is 69.0 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 88.8 mL sample of the rubbing alcohol solution? Express your answer to three significant figures. 2) How many liters of a 3.06 M K2SO4 solution are needed to provide 83.8 g of K2SO4 (molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Express your answer to three significant figures.
How many milliliters of concentrated sulfuric acid, 94.0% by weight, density 1.831 g/cm3 , are required...
How many milliliters of concentrated sulfuric acid, 94.0% by weight, density 1.831 g/cm3 , are required to prepare 250 mL of a 0.05 M solution?
Isopropyl alcohol is mixed with water to produce a 31.0% (v/v) alcohol solution. How many milliliters...
Isopropyl alcohol is mixed with water to produce a 31.0% (v/v) alcohol solution. How many milliliters of each component are present in 745 mL of this solution? Assume that volumes are additive. alcohol: mL water: mL
how do I get the molar ratios between NaBr, 1-butanol and H2SO4 used in the experiment...
how do I get the molar ratios between NaBr, 1-butanol
and H2SO4 used in the experiment sn2 reaction 1-bromobutane
Moles:
NaBr: 0.0275
Butanol: 0.0216
H2SO4: 0.00840
butanol is the limiting reagent
Experiment: 08 The S2 Reaction: 1-Bromobutane Substitution nucleophilic bimolecular (SN2) reactions can be utilized to convert primary alcohols to corresponding halogens. In this experiment, 1-butanol is treated with a nucleophile (Br) to generate the corresponding 1-bromobutane. The nucleophile in this lab is generated from an aqueous solution of NaBr....
I need to calculate the theoretical yield and percent yield for 1-bromobutane (Synthesis of 1-Bromobutane via...
I need to calculate the theoretical yield and percent yield for 1-bromobutane (Synthesis of 1-Bromobutane via SN2) using this attached data but I am having trouble figuring it out. Mass NaBr: 6.985 g Water: 7.50 mL 1-butanol: 5.00 mL Note: Look up the density of 1-butanol Mass of product container: 28.112 g Mass of product container & 1-bromobutane: 35.432 g Flame turned from blue to green when wire placed in flame Note: look up what the Beilstein test is and...
questions 1-5 QUESTION 1 How many milliliters of an 80% (V/V) solution of isopropyl alcohol would...
questions 1-5
QUESTION 1 How many milliliters of an 80% (V/V) solution of isopropyl alcohol would you need to make 355 mL of a 47.1% (v/v) solution of isopropyl alchohol? QUESTION 2 The ratio of solute to solvent expressed in some set of units is the QUESTION 3 For very dilute solution we sometimes use parts per million, also known as QUESTION 4 How many grams of NaOH would be needed to make 773 mL of a 2.76 M solution?...
how to calculate actual yield in moles and actual yield in
grams?
15g
+ CH,CH,CH,CH,OH 1-butanol NaBr + H2SO4 → CH2CH2CH2CH2Br + NaHSO4 + 1,0 sodium sulfuric 1-bromobutane bromide acid 102.9 15.0 g MM: mass: volume: moles: 74.1 9.25 g 11.4 mL 0.125 98.1 23 g 12.5 mL 0.235 137.0 117.1 g (theory) 13.4 mL (theory) 0,125 (theory) 0.145 338 1.84 bp (°C): 117 D (g/mL): 0.81 n20: 1.3991 102 1.28 1.4401
Isopropyl alcohol is mixed with water to produce a 38.0% (v/v) alcohol solution. How many milliliters of each component are present in 875 mL of this solution? Assume that volumes are additive. alcohol: mL water: ml The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. How many grams of sucrose are needed to make 695 mL of a 38.0% (w/v)...
3 part question
Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109 mmol of butanol nd excess acid and sodium bromide. (Note: the stoichiometric relationship between butanol and romobutane is 1:1) Convert the theoretical yield of 1-bromobutane to moles. Convert the moles to mmol. please clearly explain how to do this using the below information with thr correct sig figs Structure for 1-butanol Molecular weight for 1-butanol density for 1-butanol Bonpoint butanol 117.7°C 74.12 gimol 81...
Isopropyl alcohol is mixed with water to produce a 31.0% (v/v) alcohol solution. How many milliliters of each component are present in 745 mL of this solution? Assume that volumes are additive. alcohol: mL water: mL
how do I get the molar ratios between NaBr, 1-butanol
and H2SO4 used in the experiment sn2 reaction 1-bromobutane
Moles:
NaBr: 0.0275
Butanol: 0.0216
H2SO4: 0.00840
butanol is the limiting reagent
Experiment: 08 The S2 Reaction: 1-Bromobutane Substitution nucleophilic bimolecular (SN2) reactions can be utilized to convert primary alcohols to corresponding halogens. In this experiment, 1-butanol is treated with a nucleophile (Br) to generate the corresponding 1-bromobutane. The nucleophile in this lab is generated from an aqueous solution of NaBr....
questions 1-5
QUESTION 1 How many milliliters of an 80% (V/V) solution of isopropyl alcohol would you need to make 355 mL of a 47.1% (v/v) solution of isopropyl alchohol? QUESTION 2 The ratio of solute to solvent expressed in some set of units is the QUESTION 3 For very dilute solution we sometimes use parts per million, also known as QUESTION 4 How many grams of NaOH would be needed to make 773 mL of a 2.76 M solution?...
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