An activity on a PERT network has these time estimates: optimistic = 2, most likely =...

Question

Question

An activity on a PERT network has these time estimates: optimistic = 2, most likely =...

An activity on a PERT network has these time estimates: optimistic = 2, most likely = 3, and pessimistic = 10. What is its expected activity time and

variance?

A.

5; 1.78

B.

4; 1.78

C.

5; 10.67

D.

4; 10.67

E.

None of the above.

business Operations-Management

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Answer 1

Answer #1

Answer: b.4; 1.78

Expected time =(2+4(3)+10)/6

= 2+12+10/6 = 24/6 = 4

Expected time = 4

Standard deviation

=(10-2)/6

=8/6

= 1.3333

Variance =((10-2)/6)2

= 1.3333*1.3333

Variance =1.78

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Answer 2

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