Question

1) The MIPS instruction set only contains two types of conditional branch instruction, beq and bne....

1) The MIPS instruction set only contains two types of conditional branch instruction, beq and bne. Explain why the designers of MIPS considered this
to be a sensible thing to do.

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
1) The MIPS instruction set only contains two types of conditional branch instruction, beq and bne....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • Usc only the following MIPS instructions for assignment questions 3, 4 and 5: add, sub, addi,...

    Usc only the following MIPS instructions for assignment questions 3, 4 and 5: add, sub, addi, j, beq, bne, lw, sw. You may not need as many lines as we provide space for 4. (4 pts) Write a MIPS program starting at address 20 that writes a value of 488 to register $7. Next, you will test if register $10 is equal to register $7. If the values are equal, continue execution at address 48; otherwise set the value in...

  • Assume the MIPS instruction subset is redefinied to contain only the following instructions: 1. Assume that...

    Assume the MIPS instruction subset is redefinied to contain only the following instructions: 1. Assume that our MIPS instruction subset is redefined to contain only the following instructions: Instruction Instruction fetch Register read & ALU operation Data Memory Register write decode 0 ns R-format 2ns 1 ns lw ns l ns 2 ns 5 ns 1 ns ns 1 ns ns 0 0 bne The table lists the times required for each step within each instruction. Recall that with the...

  • 1. The MIPS instruction set includes several shift instructions. They include logical-shift-left ...

    1. The MIPS instruction set includes several shift instructions. They include logical-shift-left (sll), logical-shift-right (srl), and arithmetic-shift-right (sra). [2 +2 4 points] a) Why does not MIPS offer an "arithmetic-shift-left (sla)" instruction? b) Write a MIPS code to implement the logical-shift-left (sll) instruction for a machine that did not have this particular instruction? In other words, you have to write the equivalent of the sll instruction using mul, add and other instructions. Try writing the equivalent of sll Ss1, Ss2,...

  • Consider a hypothetical computer with an instruction set of only two n-but instructions. The firs...

    Consider a hypothetical computer with an instruction set of only two n-but instructions. The first bit specifies the opcode, and the remaining bits specify one of the 2-1 n-bit words of main memory. The two instructions are as follows: SUBS X: Subtract the contents of location X from the accumulator, and store the result in location X and the accumulator JUMP X: Place address X in Program Counter A word in memory may contain either an instruction or a binary...

  • Goals: To learn general-purpose register architectures. To learn encoding an instruction set. Questions: 100 points: (1)...

    Goals: To learn general-purpose register architectures. To learn encoding an instruction set. Questions: 100 points: (1) 30 points, (2) 70 points 1. (30 points) The design of MIPS provides for 32 general-purpose registers and 32 floating-point registers. If registers are good, are more registers better? List and discuss as many trade-offs as you can that should be considered by instruction set architecture designers examining whether to, and how much to increase the numbers of MIPS registers. 2. [70 points] Consider...

  • Consider a hypothetical computer with an instruction set of only two n-bit instruc- tions.The first bit...

    Consider a hypothetical computer with an instruction set of only two n-bit instruc- tions.The first bit specifies the opcode, and the remaining bits specify one of the 2-1 n-bit words of main memory. The two instructions are as follows: 12.7 SUBS X Subtract the contents of location X from the accumulator, and store the result in location X and the accumulator. Place address X in the program counter JUMPX A word in main memory may contain either an instruction or...

  • 1. Given the following instruction sequence for the MIPS processor with the standard 5 stage pipeline $10, S0. 4 addi lw S2.0(S10) add sw S2,4(510) $2, $2, $2 Show the data dependences between th...

    1. Given the following instruction sequence for the MIPS processor with the standard 5 stage pipeline $10, S0. 4 addi lw S2.0(S10) add sw S2,4(510) $2, $2, $2 Show the data dependences between the instructions above by drawing arrows between dependent instructions (only show true/data dependencies). a. Assuming forwarding support, in what cycle would the store instruction write back to memory? Show the cycle by cycle execution of the instructions as they execute in the pipeline. Also, show any stalls...

  • Consider two different implementations, M1 and M2, of the same instruction set. There are three classes...

    Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, and C) in the instruction set. M1 has a clock rate of 80 MHz and M2 has a clock rate of 100 MHz. The average number of cycles for each instruction class and their frequencies (for a typical program) are as follows: (a) Calculate the average CPI for each machine, M1, and M2. (b) Calculate the average MIPS ratings for...

  • Topics 1. MIPS instruction set architecture (ISA). 2. Performance. 3. MIPS datapath and control. Exercise 1...

    Topics 1. MIPS instruction set architecture (ISA). 2. Performance. 3. MIPS datapath and control. Exercise 1 Consider the memory and register contents shown below. Registers Ox0100 FFF8 13 ($t 5) 14 ($t6) 0x0100 FFFC 0x0101 0000 Memory 0x0000 0000 0x0001 1100 0x0A00 со00 0x1234 4321 OxBAOO OOBB 15 OXAAAA 0000 0x1111 1010 0x7FFF FFFD 0x0100 FFFO 0x0101 0008 (St7) Ox0101 0004 16 ($80) 0x0101 0008 17 ($sl) Show what changes and give the new values in hexadecimal after the following...

  • 1. Write a program in Assembly language using MIPS instruction set that reads two integer numbers...

    1. Write a program in Assembly language using MIPS instruction set that reads two integer numbers from the user named as start and end number and finds out all the prime numbers between start and end (including start and end). Your program should do the validation of both the numbers as follows: i. start number must be smaller or equal to the end number. ii. Both numbers must be positive. iii. The maximum value for the end number is 10000...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT