1. Given that z represents a standard normal random variable, provide the probabilities for the following:
solution
(A)P(z <1.56 )
Using z table
=0.9406
probability =0.9406
(B)
P(z >-0.94 ) =1 - P(z <-0.94 )
Using z table,
= 1 -0.1736
=0.8264
probability = 0.8264
(C)P (1.57 < z < 2.30)
= P(Z < 2.30) - P(Z <1.57 )
Using z table,
= 0.9893-0.9418
probability=0.0475
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