2. Hemophilia is a sex-linked recessive trait. Show, through Punnett squares, how, before clotting factor was available, it was virtually impossible for girls to get hemophilia. And show how now, with clotting factor available, girls can now get hemophilia.
Hemophilia is a inherited disorder. It is characterised by the inability to stop bleeding ( i. e , blood doesn't clots properly ). Hemophilia A and Hemophilia B are caused by the deficiency of clotting factor VIII and clotting factor XI respectively.
Case 1 -If mother is a carrier of hemophilia and father is unaffected, the girl child must be a carrier of the disease or not at all.
Case 2 - To get a girl with hemophilia , 1 of her gene of sex chromosome must be dominant ( XHX / XHXh) . The probability of getting a girl child with hemophilia is given below.
a) Crossing between affected mother (XHXh) and affected father (XHY).
b) Crossing between affected mother ( XHXh)and unaffected father (XY).
c) Crossing between unaffected mother ( XX) and affected father ( XHY).
Conclusion - The girl child is impossible to get hemophilia ,when the mother ( XXh ) is just a carrier or by an affected father (XhY ) .
A girl is hemophilic ,either her mother (XHX / XHXh ) or father is affected ( XHY ) .
* XX - unaffected mother
XY - unaffected father
XHX - affected daughter with dominant gene
XXh - carrier daughter with recessive gene
XHXh - affected daughter with both dominant gene and recessive gene
XHY - affected son with dominant gene
XhY - affected son with recessive gene
2. Hemophilia is a sex-linked recessive trait. Show, through Punnett squares, how, before clotting factor was...
6. Hemophilia is a sex-linked trait. A person with hemophilia is lacking certain proteins that are necessary for normal blood clotting. Hemophilia is caused by a recessive allele so use "XH” for normal and "Xh" for hemophilia. Since hemophilia is sex-linked, remember a woman will have two alleles (XX) but a man will have only one allele (XY). A woman who is heterozygous (a carrier) for hemophilia marries a normal man: a. What are the genotypes of the parents? b....
Hemophilia in humans is a recessive sex-linked trait. A man with hemophilia and a woman who does not have hemophilia have a daughter who does not have hemophilia. She then marries a man who does not have hemophilia. What is the probability that their first child will be a daughter with hemophilia? A daughter without hemophilia? A son with hemophilia? A son without hemophilia? If the couple has four sons, what is the probability that all four will be born...
Hemophilia is a sex-linked X-linked recessive trait. A homozygous normal woman marries a normal man whose brother has hemophilia. What are the chances of them having a hemophiliac son; hemophiliac daughter?
How to solve? Use the following information to answer question 19. Hemophilia Hemophilia is a sex-linked recessive trait. A male hemophiliac and phenotypically normal female have a daughter that is a hemophiliac. 1 19. a. Create a Punnett square that depicts the described parental cross. b. Explain why it is far more common for a male to be a hemophiliac than a female. ADLC | Biology 30
Hemophilia is a sex-linked recessive trait. If a hemophiliac male marries a carrier female, what percent of their daughters will have hemophilia? The gene for yellow body color in Drosophila is recessive and sex-linked. Its dominant allele b+ produces wild-type body color while the recessive allele, b- produces yellow body color in homozygous individuals. List the phenotypes and genotypes of the progeny from the following matings: a. yellow female x wild-type male b. wild-type (carrier) female x wild-type male c....
In humans, hemophilia is a sex linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won’t ever be carriers) X H X H = female, normal / X H Y = male, normal X H X h = female, carrier X h X h = female, hemophiliac / X h Y= male, hemophiliac Show the cross of a man who has hemophilia with a woman who is a carrier....
1. Hemophilia is a sex-linked recessive disorder. If a male hemophiliac has children with a woman who is homozygous normal (has no family history of the hemophilia trait), what percentage of his male children would be hemophiliac (so, ignore the females) (a) 50% (1/2) (b) 100% (2/2) (c) 0% (0/2) 2. To perform a test cross, you cross an organism with a a. homozygous dominant b. homozygous recessive c. heterozygote
Question 9 1 pts Hemophilia is a sex-linked trait. Assuming a 1:1 sex ratio, how many hemophilia alleles (both wild-type and disease-causing) are found in a population of 100 people. 50 150 250 100 O 200
Name Sex-linked traits are genetic char segments of DNA found on chromosomes that Sex-Linked Traits Senetic characteristics determined by genes located on sex chromosomes. Genies are and on chromosomes that carry information for protein production and that are sponsible for the inheritance of specific traits Genes exist in alternative forms called alleics. or a trail is inherited from each parent Like traits originating from genes on autosomes (non-se chromosomes), sex-linked to omosomes), sex-linked traits are passed from parents to offspring...
need help with 1 and 2 please. X-linked Recessive Traits Review X-linked traits in your textbook. 1 In cars, the Ballele produces black fur & b produces orange fur. This gene is X-linked (X & X". Both colors are expressed in heterozygotes calico). If alcat has 2 calico kittens, 1 male black kitten, and I female orange kitten, what is the ty p henotype of the father cat? (Hint: Work backwards & use a Punnett square Remember that not every...