The test of the chi-square statistic applies to the data as a whole and provides _____ as to which cells are causing rejection of H0. A. no information B. partial information C. complete information D. none of the above
Test of the chi-square statistic applies to the data as a whole and provides no information as to which cells are causing rejection of H0.
Option A is correct.
The test of the chi-square statistic applies to the data as a whole and provides _____...
What conclusion is appropriate if a chi-square test produces a chi-square statistic near zero
a …… table has data arranged for the chi square independence test a) chi square b) contingency c) t d) z
R2 = 0.5754 and n = 425. The chi-square statistic for testing the overall regression effect H0 for both slopes is 0. 575.9421: How many degrees of freedom are there for the chi-square test statistic?
R2 = 0.5754 and n = 425. The chi-square statistic for testing the overall regression effect H0 for both slopes is 0. 575.9421: How many degrees of freedom are there for the chi-square test statistic?
When we carry out a chi-square test of independence, the chi-square statistic is based on (rxc)-1 degrees of freedom, where r and c denote, respectively, the number of rows and columns in the contingency table. True or false
1. For the following data: (a) Compute the value of the chi-square test statistic. (6) Test the hypothesis that X and Y are independent at the a=0.05 level of significance. X3 Y 87 74 34 Y 12 18 X2 Poor 2. Are health and happiness related? Use a=0.05 level of significance. Health Excellent Fair Very Happy 271 261 Happiness Pretty Happy 247 Not Too Happy 33 567 103
The test statistic for goodness of fit has a chi-square distribution with k - 1 degrees of freedom provided that the expected frequencies for all categories are a. 10 or more. b. k or more. c. 2k. d. 5 or more.
A chi-square test is done in which you compare your data to a hypothesis of independent assortment. You obtain a chi square value of 11.35 which works out to a P value of 0.01. based on this information, A.) you accept the hypothesis and conclude that the genes are unlinked B.) you except the hypothesis and conclude that the genes are linked C.) You rejected the hypothesis and conclusion at the genes are unlinked D.) you reject the hypothesis and...
1.Referring to the the Goodness-of-fit data shown in table 1. The calculated Chi-sq test statistic is A. 8.0 B. 12 C. 7.85 D.8.75 Table 1 Chi-Squared goodness-of-fit test H0: Follows Uniform Distribution H1: Does not follow Uniform Distribution Category Observed Expected Contribution To Chi-Sq 1 12 8 2.000 2 7 8 0.125 3 2 8 4.500 4 7 8 0.125 5 12 8 2.000 6 8 8 0.000
a) true b) false 42. For a chi-square distributed random variable with 10 degrees of freedom and a level of sigpificanoe computed value of the test statistics is 16.857. This will lead us to reject the null hypothesis. a) true b) false 43. A chi-square goodness-of-fit test is always conducted as: a. a lower-tail test b. an upper-tail test d. either a lower tail or upper tail test e. a two-tail test 44. A left-tailed area in the chi-square distribution...