Question

A chi-square test is done in which you compare your data to a hypothesis of independent assortment. You obtain a chi square value of 11.35 which works out to a P value of 0.01. based on this information,

A.) you accept the hypothesis and conclude that the genes are unlinked

B.) you except the hypothesis and conclude that the genes are linked

C.) You rejected the hypothesis and conclusion at the genes are unlinked

D.) you reject the hypothesis and conclude that the genes are linked

Answer 1

I will go with option D) Reject hypothesis and conclude that the genes are linked.

This is because the P value is greater than the prescribed limit and hence due to that the Null Hypothesis which is The two genes are independent assorted i.e. the genes are not linked it is ruled out and Alternate Hypothesis is accepted which is the two genes do not assort independently i.e. the genes are linked together