1)
This is a normal distribution question with
This implies that
P(-0.25 < z < 0.25) = 0.1974
2)
This is a normal distribution question with
This implies that
P(-0.32 < z < 0.32) = 0.251
3)
This is a normal distribution question with
This implies that
P(-0.43 < z < 0.43) = 0.3328
4)
This is a normal distribution question with
x = 26
The z-score at x = 26.0 is,
z = 1.5
For a Standard Normal random variable Z, calculate the probability P(-0.25 < Z < 0.25). For...
A Normal random variable X has mean 20 and standard deviation 4. Calculate the probability that specific values of X exceed 26. Calculate the 36th percentile of a Standard Normal random variable. A Standard Normal random variable Z falls within an interval of values centered around zero, that is the interval -z to z, with probability 0.6. Calculate the value of z that defines that interval. A truck makes daily round trips between Charlotte and Atlanta. On 30 percent of...
We can now use the Standard Normal Distribution Table to find the probability P(-0.25 sz s 1). 0.05 0.06 0.07 0.08 0.09 -0.2 0.4013 0.3974 0.3936 0.3897 0.3859 0.00 0.01 0.02 0.03 0.04 Using these 1.0 0.8413 0.8438 0.8461 0.8485 0.8531 The table entry for z = -0.25 is 0.00 and the table entry for z = 1 is values to calculate the probability gives the following result. PC-0.25 sz s 1) P(Z < 1) - P(Z 5 -0.25) 10....
Let z be a random variable with a standard normal distribution. Calculate the indicated probability P(−1.15≤ z ≤1.55)P(−1.15≤ z ≤1.55).
4. Let Z ~ N(0,1) be a standard normal variable. Calculate the probability (a) P(1 <Z < 2). (b) P(-0.25 < < < 0.8). (c) P(Z = 0). (d) P(Z > -1).
IS Find the following probability for the standard normal random variable z. a. P(z<-1.02) b. P(z <2.03) c. P(0.68 szs2.03) d. P(-2.66szs1.56) a. P(z -1.02)(Round to four decimal places as needed.) b. Pize 2.03)=[] (Round to four decimal places as needed.) ook c. P(0.68 szs2.03) (Round to four decimal places as needed.) d.P(-2.66 s zs 1.56) = [□ (Round to four decimal places as needed.)
QUESTION 10 4 If Z is a standard normal random variable, then P(-1.25<= Z <=-0.75) is QUESTION 11 4F It is given that x, the unsupported stem diameter of a sunflower plant, is normally distributed with population mean mu=35 and population standard deviation sigma=3. What is the probability that a sunflower plant will have a basal diameter of more than 40 mm? 4 pc QUESTION 12 A random variable x is normally distributed with u = 100 and o-20, What...
ULULUI Let Z be a standard normal random variable. What is P(-2.22 <Z<0.25)? 0.2212 0.3488 0.5855 O 0.6902
given that z is a standard normal random variable what is the probability that z ≥ -2.12? a. 0.966 b. 0.017 c.4830 0.9830 From a population of 200 elements, a sample of 49 elements is selected. It is determined that the sample mean is 56 and the sample standard deviation is 14. The standard error of the mean is a. 3 b. 2 c. greater than 2 d. less than 2
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(z ≤ −1.94) = [x].
Assume Z is a random variable with a standard normal distribution and c is a positive number. If P(Z > c) = 0.25, then PC – c< < c) = 0.5. O True OFalse Exactly 50% of the area under the normal curve lies to the left of the mean. O True OFalse If X represents a random variable coming from a normal distribution and P(X < 5.2) = 0.5, then P(X > 5.2) = 0.5. O True O False