Tidal Torque
Phobos, a moon of Mars, is in a prograde orbit but orbiting within synchronous orbit.
(a) Assuming Phobos has the same density as Mars, estimate the distance from the center of Mars at which Phobos will be tidally disrupted.
(b) Calculate the corresponding period of Phonos' orbit for the situation in part (a). Compare it with the current period of 0.32 Earth days.
Tidal Torque Phobos, a moon of Mars, is in a prograde orbit but orbiting within synchronous...
Tidal Torque Phobos, a moon of Mars, is in a prograde orbit but orbiting within synchronous orbit. (a) Assuming Phobos has the same density as Mars, estimate the distance from the center of Mars at which Phobos will be tidally disrupted.
B.2 This question concerns the possible tidal disruption of a spherical moon on a circular orbit of radius r about a host planet. The planet has mass Mp, radius R and mean density pp; the moon has mass M, radius Rm rand mean density Pm You may ignore any forces beyond the moon-planet system. (i) Show that tidal forces lead to a differential acceleration, between the face of the moon closest to the planet and the moon's centre, of amplitude...
Today, the Moon’s orbit around Earth has a semi-major axis of a=384,400 km and an orbital period of 27.32166 days. a. The Moon slowly moves outward due to tidal braking of the Earth’s rotation, and at some future date the Moon will have an orbital period of 47 days. Compute the semi-major axis of the Moon’s orbit at this future date (express your answer in kilometers). semi-major axis = 5.5*10^5 km b. Today, the Moon has an angular diameter of...
6. Given that the distance to the Moon is 384000 km, and taking the Moon’s orbit around Earth to be circular, estimate the speed (in kilometers per second) at which the Moon orbits the Earth. 7. The baseline in Figure 0.19 in the textbook is 100 m and the angle at B is 60 degrees. Using the tangent function, calculate the distance from A to the tree Ch. 1 Discussion Questions 2. The benefit of our current knowledge lets us...
The tidal forces between the Earth and the Moon slowed down the Moon's rotation about its own axis until the rotation period became equal to the Moon's orbital period around the Earth as we observe today. The same effect is also slowing down the Earth's rotation about its own axis and increasing the separation \(D\) between the Moon and the Earth at a rate of \(\Delta D / \Delta t=3.8 \mathrm{~cm}\) per year. In this problem, you can ignore the...
Question 7 (0.5 points) What causes the Moon to move about 12° across the sky from one night to the next (at the same time of night, of course)? O Because the Earth is turning on its axis. O Because the Moon is moving in its orbit. The Sun has also moved 15° across the sky and gravitationally pulls the Moon with it. The celestial sphere the Moon is attached to has moved 15°. O It is an optical illusion....