What is the equilibrium pH of a 0.515 M solution of H3PO4 (aq)? (Ka1 = 7.5...

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What is the equilibrium pH of a 0.515 M solution of H3PO4 (aq)? (Ka1 = 7.5...

What is the equilibrium pH of a 0.515 M solution of H3PO4 (aq)? (Ka1 = 7.5 × 10–3 , Ka2 = 6.2 × 10–8 , Ka3 = 4.8 × 10–13) a. 1.23 b. 3.75 c. 12.32 d. 6.30 e. 7.21

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Answer 1

Answer #1

As Ka1 and Ka2 are very very small in comparison to Ka1 ,hence the concentration of hydronium ion comes from first dissociation.

[H+] = (Ka1×C)^1/2

= (7.5×0.515×10^-3)^1/2

=6.2×10^-3 M

(a) is correct option

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Answer 2

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What is the equilibrium pH of a 0.515 M solution of H3PO4 (aq)? (Ka1 = 7.5...

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