D= ∑((ni(n–1)) / (N (N-1)) i=1
To complete the calculation, the reciprocal value for D is calculated.
Thus the final value for the Simpson’s Diversity Index is 1/D.
D = the value of the Simpson’s Diversity Index (reciprocal value needed)
ni = the number of individuals in the ith sample
N = the total number of individuals in the entire sample
find Simpsons diversity index for group1
group 1:
species a= 42
species b= 6
species c= 1
species d= 5
species e= 22
species f= 4
species g= 1
species h= 3
species I = 7
D= ∑((ni(n–1)) / (N (N-1)) i=1 To complete the calculation, the reciprocal value for D is...
D= ∑((ni(n–1)) / (N (N-1)) i=1 To complete the calculation, the reciprocal value for D is calculated. Thus the final value for the Simpson’s Diversity Index is 1/D. D = the value of the Simpson’s Diversity Index (reciprocal value needed) ni = the number of individuals in the ith sample N = the total number of individuals in the entire sample find Simpsons diversity index for each group, group 1: species a= 42 species b= 6 species c= 1 species...
The one-sample -statistic for a test of Ho: u = 42 versus H1: /i < 42 based on n = 15 observations has the value 1=1.757, where Ho and Hiare the null and alternative hypotheses, respectively. The sample size is denoted by n Use this r-table to determine which two P-values bracket the P-value of the test. Report your answers in decimal form as listed in the 1-table K P-value of the test <
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