Question

D= ∑((ni(n–1)) / (N (N-1)) i=1

To complete the calculation, the reciprocal value for D is calculated.

Thus the final value for the Simpson’s Diversity Index is 1/D.

D = the value of the Simpson’s Diversity Index (reciprocal value needed)

ni = the number of individuals in the ith sample
N = the total number of individuals in the entire sample

find Simpsons diversity index for each group,

group 1:

species a= 42

species b= 6

species c= 1

species d= 22

species e= 4

speacies f= 1

species g= 3

species h= 7

group 2:

species aa= 2

speacies bb= 29

species cc= 2

speacies dd= 20

Answer 1

For group 1 (Total mo. A individuals N=42+6+1+22+4+1+3+7=86 D= senetinin nua cay2-(407 anos) - ace? * 16) 86685) 86(85) *(86(85)) . 0.236 + 0.004 +0+0.663 +0.002+0+ 0.0008 +0.006 +0.312 : The Simpson's Diversity Index = 1 - 0312 3:21 for groups (Total no. of individuals = 2 +29 +2 +20 = 53 Crow7+ 29(28) +2012 ] + [20(19) = 0.0007 + 0.295 + 0.0007 + 0.138 0.434 The Simpson's Diversity Index= 1/2 = 0.434 - 23 S Sanned with C mScanner