Independent random samples of size n1=38 and n2=86 observations, were selected from two populations. The samples from populations 1 and 2 produced x1=18 and x2=13 successes, respectively. Define p1 and p2 to be the proportion of successes in populations 1 and 2, respectively. We would like to test the following hypotheses: H0:p1=p2 versus H1:p1≠p2
(a)To test H0 versus H1, which inference procedure should you use?
A. Two-sample z procedure
B. One-sample z procedure
C. One-sample t procedure
D. Two-sample t procedure
(b) What is the standard error of (p̂ 1−p̂ 2) under the null hypothesis?
A. 0.0081
B. 0.0843
C. 0.0897
D. 0.0071
(c) What is the test statistic for this hypothesis test?
A. 1.960
B. 4.7379
C. 3.8256
D. 3.5953
(d) What is the P-value of this test?
A. Greater than 0.10
B. Between 0.05 and 0.10
C. Between 0.01 and 0.05
D. Less than 0.01
(e) Can we reject H0 in favour of H1 at the α=0.01 significance level?
A. Yes
B. No
C. We are unable to make a conclusion at this significance level.
The statistical software output for this problem is:
Hence,
a) Two Sample z procedure
b) Standard error = 0.0843
c) Test statistic = 3.8256
d) P value is less than 0.01
e) Yes
Independent random samples of size n1=38 and n2=86 observations, were selected from two populations. The samples...
Independent random samples, each containing 90 observations, were selected from two populations. The samples from populations 1 and 2 produced 50 and 42 successes, respectively. Test H0:(p1−p2)=0 against Ha:(p1−p2)≠0. Use α=0.04. (a) The test statistic is (b) The P-value is (c) The final conclusion is A. We can reject the null hypothesis that (p1−p2)=0 and accept that (p1−p2)≠0. B. There is not sufficient evidence to reject the null hypothesis that (p1−p2)=0. side note- no idea how to find a test...
Independent random samples of 180 observations were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 104 successes, and sample 2 had 113 successes. Suppose that, for practical reasons, you know that p1 cannot be larger than p2. Test the appropriate hypothesis using α = 0.10. Given: H0: (p1 − p2) = 0 versus Ha: (p1 − p2) < 0 Solve: Find the test statistic. (Round your answer to two decimal places.) z = ?? Find the...
1 point) Independent random samples, each containing 50 observations, were selected from two populations. The samples from populations 1 and 2 produced 34 and 27 successes, respectively. Test H0:(p1−p2)=0H0:(p1−p2)=0 against Ha:(p1−p2)≠0Ha:(p1−p2)≠0. Use α=0.1α=0.1. (a) The test statistic is (b) The P-value is (c) The final conclusion is A. We can reject the null hypothesis that (p1−p2)=0(p1−p2)=0 and accept that (p1−p2)≠0(p1−p2)≠0. B. There is not sufficient evidence to reject the null hypothesis that (p1−p2)=0(p1−p2)=0.
(1 point) Independent random samples, each containing 90 observations, were selected from two populations. The samples from populations 1 and 2 produced 37 and 30 successes, respectively. Test H 0 :( p 1 − p 2 )=0 H0:(p1−p2)=0 against H a :( p 1 − p 2 )≠0 Ha:(p1−p2)≠0 . Use α=0.05 α=0.05 . (a) The test statistic is (b) The P-value is (c) The final conclusion is A. We can reject the null hypothesis that ( p 1 −...
(1 point) Independent random samples, each containing 800 observations, were selected from two binomial populations. The samples from populations 1 and 2 produced 581 and 221 successes, respectively. (a) Test Ho : (p1 – P2) = 0 against Ha : (Pi – P2) # 0. Use a = 0.01 test statistic = rejection region |z| > The final conclusion is # 0. A. We can reject the null hypothesis that (p1 – P2) = 0 and accept that (p1 –...
Independent random samples of n = 150 and n = 150 observations were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 68 successes, and sample 2 had 74 successes. You wish to perform a hypothesis test to determine if there is a difference in the sample proportions P, and py: (a) State the null and alternative hypotheses. O Ho: (P1 - P2) = 0 versus Ha: (P1-P2) < 0 O Ho: (2,-) < versus H: (2,-2)...
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations. Sample 1 F1 = 23.65 = 2.50 p1 = 18 Sample 2 F2 = 25.62 = 3.28 p2 = 20 Test the null hypothesis Ho: P1 = r2 against the alternative hypothesis HA : H1 CH2 a) Calculate the test statistic for the Welch Approximate procedure. Round your response to at least 3 decimal places. Number b) The Welch-Satterthwaite approximation to the degrees of...
Independent random samples were selected from two binomial populations, with sample sizes and the number of successes given below. Population 1 2 500 500 119 148 Sample Size Number of Successes State the null and alternative hypotheses to test for a difference in the two population proportions. O Ho: (P1-P2) # O versus H: (P1-P2) = 0 O Ho: (P1-P2) = 0 versus Hy: (P1-P2) > 0 HO: (P1-P2) < 0 versus Ha: (P1-P2) > 0 HO: (P1-P2) = 0...
(1 point) Independent random samples, each containing 80 observations, were selected from two populations. The samples from populations 1 and 2 produced 63 and 51 successes, respectively. Test Ho : (P-P2against Ha: (Pi -P2)>0. Use a0.01 (a) The test statistic is (b) The P-value is (c) The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that (pi - P2) - 0. B. We can reject the null hypothesis that (pi - P2) 0 and...
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations. Sample 1 F1 = 22.49 11 = 2.54 P1 = 15 Sample 2 F2 = 27.31 3 = 3.08 P2 = 18 Test the null hypothesis HO : H1 = 2 against the alternative hypothesis HA: MI <H2 a) To save you on calculations, I will tell you that the standard error of the difference in sample means (SE(X_1 bar - X_2 bar)) is...