z is a standard normal random variable. The P(-1.8<z<2.09) equals
Group of answer choices
0.0176
0.9641
0.9458
1.02
solution
P(-1.8<z<2.09)
= P(Z <2.09 ) - P(Z <-1.8 )
Using z table,
= 0.9817 -0.0359
=0.9458
probability=0.9458
z is a standard normal random variable. The P(-1.8<z<2.09) equals Group of answer choices 0.0176 0.9641...
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